Question

PLEASE HELP!!!!!

Answer 1

Answer:6018

Step-by-step explanation:

Given Sequence

$-282-266-250-234.....$

It represent an A.P. with

first term $a=-282$

common difference $d=16$

So sum of 51 term

$S_n=\frac{n}{2}[2a+(n-1)d]$

$S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]$

$S_{51}=\frac{51}{2}\times [-564+800]$

$S_{51}=\frac{51}{2}\times [236]$

$S_{51}=51\times 118$

$S_{51}=6018$