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Svetllana [295]
3 years ago
11

PLEASE ANSWER ... Subtract-3x – 8 from 4x2 72 – 2.

Mathematics
1 answer:
agasfer [191]3 years ago
7 0
I’m guessing you meant 4x^2 (x to the power of two or x squared) rather than 4x2 (4 multiplied by two, meaning 8).

4x^2 -(-3x-8)
= 4x^2 +3x +8

72-2 = 70
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7 0
3 years ago
Suppose the roots of the equation 2x^2−5x−6=0 are α and β.Find the quadratic equation with roots 1/α and 1/β.​
pochemuha

Answer:

6x² + 5x - 2 = 0

Step-by-step explanation:

Given

2x² - 5x - 6 = 0 ← in standard form

with a = 2, b = - 5, c = - 6, then

sum of roots α + β = - \frac{b}{a} = \frac{5}{2}

product of roots = \frac{c}{a} = - 3, then

sum of new roots = \frac{1}{\alpha } + \frac{1}{\beta }

= \frac{\beta+\alpha  }{\alpha \beta }

= \frac{\frac{5}{2} }{-3} = - \frac{5}{6}

product of new roots = \frac{1}{\alpha } × \frac{1}{\beta }

= \frac{1}{\alpha\beta  } = - \frac{1}{3}

Hence the required equation is

x² + \frac{5}{6} x - \frac{1}{3} = 0 or

6x² + 5x - 2 = 0 ( multiplying through by 6 )

                           

8 0
3 years ago
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qaws [65]
Wowza that’s crazy!!!!!!!
5 0
3 years ago
Read 2 more answers
Without solving determine the number of real solutions for each quadratic equation
seropon [69]

Answer:

b^2-4b+3=0

b²-3x-b+3=0

b(b-3)-1(b-3)=0

(b-3)(b-1)=0

either

b=3 or b=1

.

2n^2 + 7 = -4n + 5

2n²+4n+7-5=0

2n²+4n+2=0

2(n²+2n+1)=0

(n+1)²=0/2

:.n=-1

.

x - 3x^2 = 5+ 2x - x^2

0=5+ 2x - x^2-x +3x^2

0=5+x+2x²

2x²+x+5=0

comparing above equation with ax²+bx +c we get

a=2

b=1

c=5

x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1

={-1±√-39}/2

3 0
2 years ago
Ellen has a beginning balance of $370 in her checking account. She writes two checks for $40 and $50 respectively and deposits $
Naily [24]
$370.00 - $40.00 = $330.00
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$280.00 + $210.00 = $490.00
Ellen now has $490.00 as her new balance.
3 0
3 years ago
Read 2 more answers
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