Answer:she need to do at least 3 hours of babysitting.
Step-by-step explanation:
you subtract how much she already has, 3$ from 25.50 and then you divide how much she makes in one hour of babysitting by how much money she needs so 22.50/7.50=3
A. I would estimate that 7 in of the ribbon
B. the estimate would be high because the longer the ribbon is the more of the ribbon would have to be cut.
C. 11.7 - 5.25 = 6.45 iris has to cut 6.45 off the longer ribbon for the ribbons to be the same length.
Answer:
The first three terms in the sequence are -4, -2, 0
Step-by-step explanation:
In any sequence n represents the position of the term in the sequence
<u><em>Examples:</em></u>
First term ⇒ n = 1
Second term ⇒ n = 2
Fifth term ⇒ n = 5
Let us solve our question
∵ The rule of the nth term is an = 2n - 6
→ We need to find the first three terms, means n = 1, 2, 3
∵ n = 1
∴ a1 = 2(1) - 6
∴ a1 = 2 - 6
∴ a1 = -4
∴ The first term is -4
∵ n = 2
∴ a2 = 2(2) - 6
∴ a2 = 4 - 6
∴ a2 = -2
∴ The second term is -2
∵ n = 3
∴ a3 = 2(3) - 6
∴ a3 = 6 - 6
∴ a3 = 0
∴ The third term is 0
The first three terms in the sequence are -4, -2, 0
Answer:
The method would use to prove that the two Δs ≅ is AAS ⇒ D
Step-by-step explanation:
Let us revise the cases of congruence:
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles and one side in the 2nd Δ
- HL ⇒ hypotenuse and leg of the 1st right Δ ≅ hypotenuse and leg of the 2nd right Δ
In the given figure
∵ The two triangles have an angle of measure 30°
∵ The two triangles have an angle of measure 70°
∵ The two triangles have a side of length 10
∴ The two triangles have two equal angles and one equal side
→ By using rule 4 above
∴ The two triangles are congruent by the AAS rule
∴ The method would use to prove that the two Δs ≅ is AAS
