Can anyone please answer these for me?

Andy has a collection of movie dvds. in andys collection 3/5 of the dvds are action 1/4 of the dvds are comedy. andy said that 4

Cerrena [4.2K]

This question is based on greatest common multiple.

Answer:

Cynthia is right that Andy made an error.

Step-by-step explanation:

As per Andy, action dvds are = $\frac{3}{5}$

And comedy dvd's are = $\frac{1}{4}$

So, in total these become = $\frac{3}{5}+ \frac{1}{4}$

= $\frac{12+5}{20}$ = $\frac{17}{20}$

This is not 4/9 as per Andy.

6 0

3 years ago

What is the Greatest Common Factor of the two monomials?<br> 15a²b, 35ab2

m_a_m_a [10]

Answer:

5ab

Step-by-step explanation:

To find the greatest common factor (GCF), you will need to find the largest value that both of these monomials can be divided by. There are three different parts to these monomials: the number value, variable a, and variable b.

Find the largest number of each element that can be divided by both.

Numbers: the GCF of 15 and 35 is 5 (15/5 = 3, 35/5 = 7, 3 and 7 are prime numbers and therefore, cannot be divided further)

Variable a: the GCF of a² and a is a

Variable b: the GCF of b and b² is b

Therefore, the GCF is 5ab.

8 0

3 years ago

Occasionally an airline will lose a bag. Suppose a small airline has found it can reasonably model the number of bags lost each

julia-pushkina [17]

Answer:

a) The probability that the airline will lose no bags next monday is 0.1108

b) The probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227

c) I would recommend taking a Poisson model with mean 4.4 instead of a Poisson model with mean 2.2

Step-by-step explanation:

The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

$P(X=k) = \frac{e^{-2.2} * {2.2}^k }{k!}$

a)

$P(X=0) = \frac{e^{-2.2} * {2.2}^0 }{0!} = 0.1108$

The probability that the airline will lose no bags next monday is 0.1108.

b) Note that $P(X \in \{0,1,2\} = P(X=0) + P(X=1) + P(X=2)$ . And

$P(X=0)+P(X=1)+P(X=2) = e^{-2.2} * (1 + 2.2 + 2.2^2/2) = 0.6227$

Therefore, the probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227.

c) If the double of flights are taken, then you at least should expect to loose a similar proportion in bags, because you will have more chances for a bag to be lost. WIth this in mind, we can correctly think that the average amount of bags that will be lost each day will double. Thus, i would double the mean of the Poisson model, in other words, i would take a Poisson model with mean 4.4, instead of 2.2.

6 0

3 years ago

Which ordered pairs make both inequalities true? Check all that apply.

Alex17521 [72]

I JUST TOOK THE TEST AND THE ANSWER IS D

8 0

3 years ago

Read 2 more answers

I need help I been stuck in this since last week help I don’t want to get it wrong please help

Virty [35]

Answer:

=3 + 4/12 + 3/12

Step-by-step explanation:

To make 1/3 into a twelfth, you have to multiply the 3 by 4 to get 12. Whatever you do to the top you have to do to the bottom, meaning that you have to multiply 1 by 4 to get 4 on top.

To make 1/4 into a twelfth, you have to multiply the 4 by 3 to get 12. Whatever you do to the top you have to do to the bottom, meaning that you have to multiply 1 by 3 to get 3 on top.

8 0

3 years ago