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marta [7]
3 years ago
14

PLEASE HELP!!!! THNX ALOT FOR HELPING Correct answer with explanation gets brainliest

Mathematics
2 answers:
zepelin [54]3 years ago
5 0

The first step to solve this problem is to solve for the area of the square. The formula for the area of the square is:

A = a^2

Where a = measurement of the side of the square

A = 7^2

A = 49 cm^2

The second step is to solve for the area of the circle. The diameter of the circle can be drawn out of the side of the square which is 7 cm. Therefore, the radius of the circle is 3.5 cm. The formula in solving the area of the circle is:

A = pi (r)^2

A = 3.14 (3.5)^2

A = 3.14 (12.25)

A = 38.465 cm^2

To solve for the area of the shaded region, you have to deduct the area of the circle to the area of the square.

Asquare – Acircle = Area of the shaded region

49 cm^2 – 38.465 cm^2 = 10.54 cm^2 is the area of the shaded region

GrogVix [38]3 years ago
3 0
Is there more to it?
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Answer:

  16. a: (-90°, (4, 3)); b: (90°, (0, 3)); c: (-90°, (0, 0))

  17. a: (down, (4, -1)); b: (right, (4, 3)); c: (up, (5, 2))

Step-by-step explanation:

We don't know what notation you're used to seeing for rotations. Here. we'll use the form [degrees CCW, (center)]. (CW angles are negative.) In any rotation, the center is the point that is invariant (remains in the same place)

16.

a) The tail is invariant, so the rotation is (-90°, (4, 3)).

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17.

a) The tail is invariant, so the arrow is pointing down with the tip at (4, -1).

b) The center is invariant, so the arrow is reversed. It is pointing right with the tip at (4, 3).

c) Point (2, 3) is invariant, so the arrow is pointing up with the center at (5, 0). The tip is at (5, 2).

_____

<em>Additional comment</em>

If you have trouble visualizing these rotations, you might find it useful to trace the arrow on a piece of (semi-)transparent medium (plastic or tracing paper) so that you can move it as required to match the descriptions in the problem statement. A pin, or a dot on your tracing, can serve to fix the center of rotation. A little hands-on never hurts in math and geometry.

8 0
3 years ago
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