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Marta_Voda [28]
3 years ago
14

A rectangular pyramid. The rectangular base has a length of 10 centimeters and a width of 2 centimeters. 2 triangular sides have

a base of 2 centimeters and a height of 8 centimeters. 2 triangular sides have a base of 10 centimeters and a height of 6.3 centimeters.
What is the surface area of the rectangular pyramid shown?
Mathematics
2 answers:
pentagon [3]3 years ago
6 0

Answer:

99

Step-by-step explanation:

dexar [7]3 years ago
4 0

Answer:

99 cm2

Step-by-step explanation:

<u>1. to break this up a bit first find the area of the base</u>

10*2 = 20

<u>2. now 2 triangular sides with the base of 2</u>

2*8/2= 8 (each triangle is 8 cm2)

there's two of them so it's 16

<u>3. now the last two triangular sides</u>

10*6.3/2=31.5

there's two of them so it's 63

<u>4. add it all up: 20 + 16 + 63 =99</u>

<u />

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Step-by-step explanation:

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8 0
3 years ago
Bottles of a popular cola drink are supposed to contain 300 ml of cola. There is some variation from bottle to bottle because th
Ksju [112]

Answer:

We conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

Step-by-step explanation:

We are given that Bottles of a popular cola drink are supposed to contain 300 ml of cola. The distribution of the contents is normal with standard deviation of 3 ml.

A student who suspects that the bottler is under-filling measures the contents of six bottles. The results are: 299.4, 297.7, 301.0, 298.9, 300.2, 297.0

<u><em>Let </em></u>\mu<u><em> = mean contents of cola bottles.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq  300 ml   {means that the mean contents of cola bottles is more than or equal to the advertised 300 ml}

Alternate Hypothesis, H_A : \mu < 300 ml   {means that the mean contents of cola bottles is less than the advertised 300 ml}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about the population standard deviation;

                       T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean contents of cola bottle = \frac{\sum X}{n} = 299.03 ml

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            n = sample of bottles = 6

So, <em><u>test statistics</u></em>  =  \frac{299.03-300}{\frac{3}{\sqrt{6} } }     

                               =  -0.792

<em>Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is more than the critical value of z as -0.792 > -1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

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