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2 years ago

If two lines are parallel, and one line has a slope of 3/2, what is the slope of the other line?

Mathematics

1 answer:

agasfer [191]2 years ago

6 0

Parallel lines have the same slope so it would be 3/2 for the other line as well.

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Line QR contains (2, 8) and (3, 10) Line ST contains points (0, 6) and (-2, 2). Lines QR and ST are (4 points)

Inessa [10]

Slope formula:
m = y2 - y1 / x2 - x1

Line QR: (2,8) (3,10)
m = 10 - 8 / 3 - 2 = 2 / 1 = 2

Line ST: (0,6) (-2,2)
m = 2 - 6 / -2 - 0 = -4/-2 = 2

<span>c. parallel because the slopes are the same</span>

3 0

2 years ago

X=2x+3-17 how do i solve this

nikitadnepr [17]

Answer:

x=-4.67

Step-by-step explanation:

add like terms 3-17

then take x=2x-14

add 2x to both sides

3x=-14

divide by 3 and you get your answer

5 0

2 years ago

Read 2 more answers

Find the measures of the angles a-k.

denis-greek [22]

A = 54 because alternate interior angles

b = 72 because 54+54=108 and 180-108=72

c = 108 because b and c are supplemental angles

d = 72 because b and d are corresponding angles

e = 162 because 72+90=162 and definition of a straight line

f = 18 because definition of a straight line

g = 81 because definition of an isosceles triangle

h = 49.5 because vertical angles and definition of an isosceles triangle

i = 130.5 because definition of a straight line

j = 31.5 because 49.5-18=31.5

k = 99 because corresponding angles

bcegk = 540

5 0

2 years ago

The formula for converting celsius to fahrenheit is F = 9/5C+32.

NISA [10]

Step-by-step explanation:

thats is all,just subject of formula

7 0

11 months ago

You are working in a primary care office. Flu season is starting. For the sake of public health, it is critical to diagnose peop

Aleksandr-060686 [28]

Answer:

E. 0.11

Step-by-step explanation:

We have these following probabilities:

A 10% probability that a person has the flu.

A 90% probability that a person does not have the flu, just a cold.

If a person has the flu, a 99% probability of having a runny nose.

If a person just has a cold, a 90% probability of having a runny nose.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem, we have that:

What is the probability that a person has the flu, given that she has a runny nose?

P(B) is the probability that a person has the flu. So P(B) = 0.1.

P(A/B) is the probability that a person has a runny nose, given that she has the flu. So P(A/B) = 0.99.

P(A) is the probability that a person has a runny nose. It is 0.99 of 0.1 and 0.90 of 0.90. So

$P(A) = 0.99*0.1 + 0.9*0.9 = 0.909$

What is the probability that this person has the flu?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.1*0.99}{0.909} = 0.1089 = 0.11$

The correct answer is:

E. 0.11

5 0

2 years ago