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Alenkinab [10]
3 years ago
9

The fine schedule for overdue books at the county library is modeled by values in the table

Mathematics
2 answers:
HACTEHA [7]3 years ago
7 0

Answer:

I beleive the answer is choice B...

Step-by-step explanation:

In the chart if you divide the number of days over due to the cost of the fine, you get 5/2 every time. therefore, if y is the cost in cents and x is the days overdue, you would multiply x5/2 or y=5/2x, so your answer is B (y=5/2x)

guajiro [1.7K]3 years ago
6 0

Answer:

What is the table? what are the values? If you can't insert a picture please type the like f(x)= y

Step-by-step explanation:

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Geometry- I need an answer for x and y.
elixir [45]

Answer:

x = 13sqrt(3) ft = 22.5 ft

y = 13 ft

Step-by-step explanation:

The triangle is a 30-60-90 right triangle.

The ratio of the lengths of the sides is

short leg : long leg : hypotenuse = 1 : sqrt(3) : 2

From the ratio above we see that the hypotenuse is twice the short leg.

The long leg is sqrt(3) times the short leg.

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Step-by-step explanation:

To be rational means to be able to express the result as the ratio of two whole numbers.

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The diagonals of a rhombus measures 6cm and 8cm, what is the perimeter of this rhombus?
Kamila [148]
<h2><u>Diagram</u><u>:</u><u>-</u></h2>

\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(1.6,4)\qbezier(1.6,4)(1.6,4)(6.6,4)\qbezier(6,1)(6,1)(6.6,4)\qbezier(6.6,4)(6.6,4)(1,1)\qbezier(1.6,4)(1.6,4)(6,1)\put(0.7,0.5){\sf A}\put(6,0.5){\sf B}\put(1.4,4.3){\sf D}\put(6.6,4.3){\sf C}\end{picture}

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The diagonals of the Rhombus= d1 & d2=6cm and 8cm

Let the Side=a

As we know that in a Rhombus

{\boxed{\sf side=\sqrt {\left ({\dfrac{d1}{2}}\right)^2+\left ({\dfrac {d2}{2}}\right)^2}}}

  • Substitute the values

{:}\longmapsto\sf a=\sqrt {\left ({\dfrac {6}{2}}\right)^2+\left ({\dfrac {8}{2}}\right)^2 }

{:}\longmapsto\sf a=\sqrt {(3)^2+(4)^2}

{:}\longmapsto\sf a=\sqrt {9+16}

{:}\longmapsto\sf a=\sqrt{25}

{:}\longmapsto\sf a=5cm

<h2>_____________</h2><h3>Again </h3>

we know that in a Rhombus

\boxed{\sf Perimeter=4a}

  • Substitute the values

{:}\longmapsto\sf Perimeter=4×5

{:}\longmapsto\sf Perimeter=20cm

\thereforePerimeter of the rectangle is 20cm.

5 0
3 years ago
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