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Len [333]
3 years ago
14

Approximately 64​% of films are rated R. If 700 films were recently​ rated, how many were rated​ R?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0
448 films were rated R
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In 1990, the price of a gallon of unleaded gasoline was $1.37. In 1998, it was $1.02 per gallon. What is the decrease expressed
mojhsa [17]
The decrease is 35c

Q= X/100 of $1.37 = 0.35

1.37x/100 = 0.35

1.37x = 35 then divide each side by 1.37

Result is 25.5474453 percent, round up to nearest tenth.
Answer is 25%

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4 years ago
How to simplify 8x-6x<br>​
julsineya [31]
<h2>You simplify 8x-6x by:</h2>

subtracting 6x from 8x. It's quite simple to deal with small two-part numbers like these. After subtracting 6x from 8x, you will get the answer 2x.

Quick Answer:

You simply 8x-6x by subtracting 6x from 8x, and then you will get the answer 2x

<u><em>HAVE A NICE DAY</em></u>

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2 years ago
Jane walks 5 meters east, then 12 meters north.
anzhelika [568]
43 degrees is her displacement
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3 years ago
The box plot shows the undergraduate in-state tuition per credit hour at four-year public colleges. 0 300 600 900 1,200 $1,500 a
kkurt [141]

Answer:

(a) The median estimate is 450.

(b) The first and third quartiles are 300 and 750 respectively.

(c) The interquartile range is 450.

(d) The particular value which is less than 150 or it is more than 1200, is considered as an outlier.

(e) Yes, there is one outlier in our data which is the value of 1,500.

(f) The distribution is positively skewed.

Step-by-step explanation:

We are given that the box plot shows the undergraduate in-state tuition per credit hour at four-year public colleges. 0, 300, 600, 900, 1,200, 1,500.

(a) As we can see in the box plot that the middlemost data lies between 300 and 600, that means;

Median is given by the average of the two numbers, i.e;

             Median =  \frac{300+600}{2}

                           =  \frac{900}{2}  = 450

So, the median estimate is 450.

(b) As we know that the first quartile represents 25% of the data values and the third quartile represents 75% of the data values.

So, from the box plot given; we can observe that the first quartile, Q_1 = 300 and the third quartile lies between the values of 600 and 900, i.e;

Third quartile, Q_3 = \frac{600+900}{2}

                             =  \frac{1500}{2}  = 750

So, the first and third quartiles are 300 and 750 respectively.

(c) The interquartile range is given by the following formula;

          Interquartile range = Third quartile - First quartile

                                          =  Q_3-Q_1

                                          =  750 - 300 = 450

(d) From the box plot; it is clear that if the particular value is less than 150 or it is more than 1200, then it is considered as an outlier.

(e) Yes, there is one outlier in our data which is the value of 1,500.

(f) The distribution is positively skewed because the more values are on the right side of the curve and it skewed towards the right.

4 0
4 years ago
Fraction<br><img src="https://tex.z-dn.net/?f=%20-%206%20%5Cdiv%20%20%5Cfrac%7B4%7D%7B5%7D%20" id="TexFormula1" title=" - 6 \div
otez555 [7]

-6\div\dfrac{4}{5}=-\dfrac{\not6^3}{1}\cdot\dfrac{5}{\not4_2}=-\dfrac{3}{1}\cdot\dfrac{5}{2}=-\dfrac{15}{2}=-7\dfrac{1}{2}

8 0
3 years ago
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