The length of q, to the nearest 10th of a centimeter is 7.6 cm.
Given in question,
In ΔOPQ,
o = 9.2 cm
p = 2.4 cm
∠Q = 37°
Cosine formula ⇒ cos θ = 
Putting the values in equation,
cos 37 = 
0.799 = 
0.799*44.16 = 90.4 - 
32.28 = 90.4 -
= 90.4 - 32.28
= 58.12
q = 7.6 cm (to nearest 10th)
Hence, length of q is 7.6 cm.
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Answer:
No
Step-by-step explanation:
The line, to fit the data, must pass through a majority of the given points and follow the path that the data is leading. The given line passes through only a few of the points and goes on a different path than the given data. So, it does not fit.
Good luck ^^
4 times 18 is 72.
So. going from there
The length is 3 times the width. subtract 3 since this is the new and not the original. you have 15
and the width is diminished by one so you have to add one.
the original dimensions is 5 for the width and 15 for the length.
Hope this helped :)
Answer:
Step-by-step explanation:
Question 1
System of equations is,
y = -6x -------(1)
y = -4x - 2 ---------(2)
Substitute the value of y from equation (1) to equation (2)
-6x = -4x - 2
-6x + 4x = -2
-2x = -2
x = 1
From equation (1)
y = -6(1)
y = -6
Question (2)
System of equations is,
-y = x --------(1)
3x + 5y = 20 ---------(2)
Substitute the value of x from equation (1) to equation (2)
3(-y) + 5y = 20
-3y + 5y = 20
2y = 20
y = 10
From equation (1)
-y = x
x = -10
Question (3)
System of the equations is,
y = -2x - 7 --------(1)
9x - 10y = 12 ----------(2)
Substitute the value of y from equation (1) to equation (2)
9x - 10(-2x - 7) = 12
9x + 20x + 70 = 12
29x = 12 - 70
29x = -58
x = -2
From equation (1)
y = -2(-2) - 7
y = 4 - 7
y = -3
First, since it's given the angle PRS=98 degrees we can find x.
(3x-8)+(2x+6)=98 we can solve for x
after solving this we find that
x=20
Now we can solve for angle QRS
2x+6 plug in our values and we get
40+6, which equals 46 degrees
