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3 years ago

A circular garden has a diameter of 20 yards. What is the area of the garden to the

Mathematics

1 answer:

marissa [1.9K]3 years ago

4 0

Answer:314

Step-by-step explanation: To find area you use the formula πr^2. Your radius is 10 (since it is half your diameter). Plug it in to get π(10)^2. or 100π. Then just substitute 3.14 for π. You have 100 times 3.14 which equals 314

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Given a long algebraic equation, what are some strategies that you can use to make simplifying and evaluating the equation more

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Answer:

See explanation

Step-by-step explanation:

Given a long algebraic equation, the like terms can be collected. When you collect like terms, you reduce the length of the algebraic equation.

After that, you can factorize the equation where possible. When you factorize the equation. It becomes quite easier to solve it efficiently.

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Line segment AB is translated 5 units right and 2 units down followed by a rotation of 180o about the origin. The resulting imag

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Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h

Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that $r = 0.047$

$172000 in 2004

This means that $P(0) = 172000$

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

$P(t) = P(0)(1+r)^{t}$

$249000 = 172000(1.047)^{t}$

$(1.047)^{t} = \frac{249000}{172000}$

$\log{(1.047)^{t}} = \log{\frac{249000}{172000}}$

$t\log(1.047) = \log{\frac{249000}{172000}}$

$t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}$

$t = 8.05$

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

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3 years ago