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3 years ago

What is 75 1/5+ 82/14

Mathematics

2 answers:

Igoryamba3 years ago

7 0

5462/35=156.05714
I hope this helps

lana [24]3 years ago

3 0

2837/35 hope this helps

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There are 5 kids who want to start a game of Red Rover. Then 12 more kids come to play. If there are 2 teams in Red Rover, which

mixas84 [53]

Answer: The answer is one will have 8 and one will have 9 so roughly 8

Step-by-step explanation

So to start we need to add all the kids together that are playing

5+12= 17

Now we need to divide the number of kids by the number of teams that there are

17 divided by 2=8.5

So each team will have 8 but one will have nine

Hope this helps :D

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3 years ago

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When 31 times a number is increased by 40 the answer is the same as two 200 is decreased by the number

storchak [24]

$x-\ number\\\\
31x+40=200-x\ \ \ | add\ x\\\\
32x+40=200\ \ \ | subtract\ 40\\\\
32x=160\ \ \ \ | divide\ by\ 32\\\\x=5\\\\Number\ is\ 5.$

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3 years ago

What value is greater 9 or -3

Blizzard [7]

Answer:9

Step-by-step explanation:

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3 years ago

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I’ll literally give u sm points HELP Two sides and an angle (SSA) of a triangle are given. Determine whether the given measureme

Norma-Jean [14]

Answer:

The answer is B

Step-by-step explanation:

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3 years ago

Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un

erica [24]

At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

$\bf \textit{Periodic Exponential Decay}\\\\
A=I(1 - r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &1013\\
I=\textit{initial amount}\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &0\\
p=period\to &1000
\end{cases}
\\\\\\
1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I$

so, the inital amount is 1013, when t = 0,

$\bf \textit{Periodic Exponential Decay}\\\\
A=I(1- r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &1013\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &t\\
p=period\to &1000
\end{cases}
\\\\\\
A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}$

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.

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3 years ago