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Maslowich
3 years ago
13

A number k is less than 3 units from 10. What's the absolute value inequality???

Mathematics
1 answer:
Brrunno [24]3 years ago
6 0

It would be: k+3 = 10

subtracting 3 from both sides,

k+3-3 = 10-3

k=7

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Answer:

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Step-by-step explanation:

<h3><u>1</u><u>7</u> ÷ <u>8</u><u> </u></h3><h3>2 3</h3>

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<h3>=<u> </u><u> </u><u>1</u><u>7</u><u> </u><u>×</u><u> </u><u> </u><u>3</u></h3><h3> 2 × 8</h3>

The answer will be <u>5</u><u>1</u><u> </u>

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<h3>= <u>5</u><u>1</u></h3><h3> 16</h3>

Simplifying 51/16 , the answer is

<h3>= 3 <u> </u><u>3</u><u> </u></h3><h3><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>1</u><u>6</u></h3>

<u>l</u><u> </u><u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>❤</u><u>❤</u>

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3 years ago
What is the solution-2|2.2x-3.3|=-6.6
mylen [45]

Solution, solve\:for\:x,\:-2\left|2.2x-3.3\right|=-6.6\quad :\quad x=0\quad \mathrm{or}\quad \:x=3

Steps:

-2\left|2.2x-3.3\right|=-6.6

\mathrm{Divide\:both\:sides\:by\:}-2,\\\frac{-2\left|2.2x-3.3\right|}{-2}=\frac{-6.6}{-2}

\mathrm{Simplify},\\\left|2.2x-3.3\right|=3.3

|f\left(x\right)|=a\quad \Rightarrow \:f\left(x\right)=-a\quad \mathrm{or}\quad \:f\left(x\right)=a,\\2.2x-3.3=-3.3\quad \quad \mathrm{or}\quad \:\quad \:2.2x-3.3=3.3

2.2x-3.3=-3.3,\\\mathrm{Add\:}3.3\mathrm{\:to\:both\:sides},\\2.2x-3.3+3.3=-3.3+3.3,\\\mathrm{Refine},\\2.2x=0,\\\mathrm{Multiply\:both\:sides\:by\:}10,\\.2x\cdot \:10=0\cdot \:10,\\\mathrm{Refine},\\22x=0,\\\mathrm{Divide\:both\:sides\:by\:}22,\\\frac{22x}{22}=\frac{0}{22},\\\mathrm{Simplify},\\x=0

2.2x-3.3=3.3,\\\mathrm{Multiply\:both\:sides\:by\:}10,\\2.2x\cdot \:10-3.3\cdot \:10=3.3\cdot \:10,\\\mathrm{Refine},\\22x-33=33,\\\mathrm{Add\:}33\mathrm{\:to\:both\:sides},\\22x-33+33=33+33,\\\mathrm{Simplify},\\22x=66,\\\mathrm{Divide\:both\:sides\:by\:}22,\\\frac{22x}{22}=\frac{66}{22},\\\mathrm{Simplify},\\x=3

\mathrm{Combine\:the\:ranges},\\x=0\quad \mathrm{or}\quad \:x=3

\mathrm{The\:Correct\:Answer\:is\:x=0\quad \mathrm{or}\quad \:x=3}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

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