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Westkost [7]
3 years ago
8

A truck’s position relative to a car’s position is -60 feet. The car and the truck move in the same direction, but the car moves

5 feet per second faster for 8 seconds. What operations could be used to find the truck’s relative position after 8 seconds? Explain
Mathematics
1 answer:
ZanzabumX [31]3 years ago
7 0

Answer:

I think its false

Step-by-step explanation:

the car went 8 second faster

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Answer (C) 50 degrees

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1.43

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1.43 or  1  43/100 turned into a percent is 143%

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A triangle has vertices X(2, 1), Y(5, 4), and Z(5, 1). What is the area of the triangle?
pochemuha

Answer:

Step-by-step explanation:

They gave you an easy triangle. You can tell by the coordinates that X and Z are horizontally aligned, and Y and Z are vertically aligned, so Z is a right angle.

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If the area of a square is 32ft^2 how long is its diagonal
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Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

8 0
3 years ago
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