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Tatiana [17]
3 years ago
7

Simplify and give term,coefficient,and constant for each one

Mathematics
2 answers:
Rama09 [41]3 years ago
8 0

Answer:

7m-3x-1

10x+26

7x-12

Step-by-step explanation:

3m - 1 + 4m -3x

sum terms by the same variable:

3m+4m=7m

we have:

7m-3x-1

7(3+2x)-4x+5

apply the distributive property:

7*3+7*2x-4x+5

we have:

10x+26

3x+4(x-3)

apply the distributive property:

3x+4*x-12

we have:

7x-12

Tpy6a [65]3 years ago
8 0
<h2>Answer with explanation:</h2>

<u>Term--</u>

Terms of the algebraic expression are the parts of the expression which are separated by mathematical operators.

<u>Coefficient--</u>

Coefficients are the multiples which are attached just before the variable in the variable term.

<u>Constant--</u>

The term which does not contain variable.

a)

3m-1+4m-3x

on combining the like terms we have:

3m+4m-1-3x\\\\=7m-1-3x

  • There are three terms:

           7m,1\ and\ 3x

  • Also, the coefficients are:

            7\ and -3

  • and the constant term is:

                -1

b)

7(3+2x)-4x+5

on simplifying.

=7\times 3+7\times (2x)-4x+5\\\\=21+14x-4x+5\\\\=14x-4x+21+5\\\\=10x+26

  • There are two terms:

         10x\ and\ 26

  • Also, the coefficient is:

             10

  • and the constant term is:

               26

c)

3x+4(x-3)

on simplifying the given expression:

=3x+4\times x+4\times (-3)\\\\=3x+4x-12\\\\=7x-12

  • There are two terms:

                7x\ and\ 12

  • Also, the coefficient is:

                     7

  • and the constant term is:

                        -12

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Question is Incomplete;Complete question is given below;

Arla and kal both work in jobs they get paid by the hour in their first week on the job they each worked 40 hours and together there total earnings were $1300 in their second week on the job business was slow so arla worked 20 hours and kal worked 16 hours their total pool earning was $580 what is each persons hourly wage.

Answer:

The hourly wage of Arla is $15 and hourly wage of Kal is $17.5.

Step-by-step explanation:

Let the hourly wage of Arla be 'x'

Also Let the hourly wage of Kal be 'y'

Now Given:

first week on the job they each worked 40 hours and together there total earnings were $1300

So we can say that;

40x+40y=1300   ⇒ equation 1

Also Given:

Number of hours worked by Arla in second week = 20

Number of hours worked by Kal in second week = 16

Total Money earned in second week = $580

So we can say that;

20x+16y=580   ⇒ equation 2

Now Multiplying equation 2 by 2 we get;

2(20x+16y)=580\times2

Applying Distributive property we get;

40x+32y =1160   ⇒ equation 3

Now Subtracting equation 3 from equation 1 we get;

(40x+40y)-(40x+32y)=1300-1160\\\\40x+40y-40x-32y=140\\\\8y=140

Now Dividing both side by 8 we get;

\frac{8y}{8}=\frac{140}{8}\\\\y= \$17.5

Now Substituting the value of y in equation 1 we get;

40x+40y=1300\\\\40x+40\times17.5 =1300\\\\40x+700=1300\\\\40x=1300-700\\\\40x=600\\\\x=\frac{600}{40}\\\\x=\$15

Hence The hourly wage of Arla is $15 and hourly wage of Kal is $17.5.

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4 years ago
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