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1 year ago

What is the approximate length of the apothem? 0. 4 cm 0. 8 cm 1. 5 cm 1. 9 cm.

Mathematics

1 answer:

arsen [322]1 year ago

7 0

The length of apothem for a regular hexagon with radius of 18 cm and side of 18 cm is 15.6 cm

<h3>What is apothem?</h3>

The apothem of a regular polygon is a line segment from the center to the midpoint of one of its sides.

Let a represent the length of the apothem. Hence half of the side = 18/2 = 9 cm.

Using Pythagoras:

18² = a² + 9²

The length of apothem for a regular hexagon with radius of 18 cm and side of 18 cm is 15.6 cm

Find out more on apothem at: brainly.com/question/369332

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Write the inequality shown in the graph below:

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Answer:

y < 4

Step-by-step explanation:

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3 years ago

brooke found the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form as follows

Goryan [66]

Answer:

The equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is $\mathbf{y=-4x-3}$

Step-by-step explanation:

Equation of line passing through the points (-7,25) and (-4,13) in slope-intercept form.

The general equation of slope-intercept form is: $y=mx+b$

First we need to find slope

The formula used for finding slope is: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We are given: $x_1=-7, y_1=25, x_2=-4, y_2=13$

Putting values in formula and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{13-25}{-4-(-7)}\\Slope=\frac{13-25}{-4+7}\\Slope=\frac{-12}{3}\\Slope=-4$

So, slope m= -4

Now finding y-intercept

Using slope m=-4 and point (-7,25) we can find y-intercept

$y=mx+b\\25=-4(-7)+b\\25=28+b\\b=25-28\\b=-3$

So, y-intercept b =-3

Now, the equation of required line having slope m=-4 and y-intercept b=-3 is:

$y=mx+b\\y=-4x-3$

So, the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is $\mathbf{y=-4x-3}$

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Answer:

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Step-by-step explanation:

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3 years ago

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liubo4ka [24]

Answer:

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Step-by-step explanation:

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3 years ago

F(x) = -3/4 x + 8<br> I need help with this

mrs_skeptik [129]

Umm maybe try:

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