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Darya [45]
3 years ago
14

The 2 ft side length of the scale drawing corresponds to a side length of 120 feet for the actual skate park. What is the scale

factor?
Mathematics
2 answers:
SOVA2 [1]3 years ago
5 0

Answer:

The scale factor is \frac{1}{60}

Step-by-step explanation:

we know that

The scale factor is equal to the ratio between the side length of the scale drawing to the corresponding side length in the actual

so

\frac{2}{120}=\frac{1}{60}

ahrayia [7]3 years ago
3 0

Answer:

1/60

Divide

Step-by-step explanation:

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vfiekz [6]

Answer:

hi, have a great day

Step-by-step explanation:

Correct option is

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f(x)=x

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5 0
2 years ago
Read 2 more answers
PLS HELP ITS URGENT question attached
erma4kov [3.2K]

Answer:

i think the first one is 5.66 ill keep solving idk how much time you have.

Step-by-step explanation:

5 0
3 years ago
Y=6xy = 5x + 7 substitution
Naddik [55]

Answer:

Step-by-step explanation:

hello :

y=6x...(*)

y = 5x + 7...(**)

by (*) put the value of y in(**) :

6x=5x+7

6x-5x=7

x=7   but  y=6x   so : y=42

the system solution is (7,42)

7 0
3 years ago
A model rocket is launched directly upward at a speed of 50 meters per second from a height of 8 meters. The function f(t)=−4.9t
Gnoma [55]

Answer:

t=\frac{-50 -\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= 10.36

t=\frac{-50 +\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= -0.158

And since the time can't be negative we have that:

t= 10.36 seconds

So the answer for this case would be after 10.36 seconds the rocket will hit the ground

Step-by-step explanation:

For this case we have the function of the height in terms of the time givenby:

h(t) = -4.9t^2 +50 t+8

And we want to known when the rockect hit the ground and for this case we need to solve the equation h=0

-4.9t^2 +50 t+8 =0

And as we can see we have a quadratic equation like this one:

ax^2 +bx+c

Where: a =-4.9 , b =50 c =8

And the general solutions are given by:

x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}

If we replace the values that we have we got:

t=\frac{-50 -\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= 10.36

t=\frac{-50 +\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= -0.158

And since the time can't be negative we have that:

t= 10.36 seconds

So the answer for this case would be after 10.36 seconds the rocket will hit the ground

6 0
4 years ago
Can somebody please help!!!!
shusha [124]

Answer:

2. x^{2} + (y+5)^{2}=6

3a. (-3,0)

3b. (x+3)^{2} + (y+2)^{2} = 4

4a. (0,6)

4b. (x+1)^{2} + (y-6)^{2}=1

Step-by-step explanation:

In the photo attachment

5 0
4 years ago
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