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3 years ago

I'm still so confused someone please help!! I don't get the formula to figure out :(

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

8 0

Try using A=1/2bh
50 is the height in this but the base is confusing me, unless its 97 yards too, unlikely.

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(2x−12)+( 1 2 xy−10) (2x-12)+(12xy-10) for x=8 x=8 and y=2

Ratling [72]

(2(8)-12)+(12(8)(2)-10)
(16-12)+(132-10)
4+122=126
THE ANSWER WOULD BE 126 :D

5 0

3 years ago

Which function is quadratic?

AveGali [126]

Answer:

g(x) is a quadratic function ⇒ 2

Step-by-step explanation:

The quadratic function is the function that has 2 as the greatest power of the variable

The form of the quadratic function is f(x) = ax² + bx + c, where a, b, and c are constant

Let us use the information above to solve the question

∵ f(x) = $1.5^{x}$

∵ x is the exponent of the base 1.5

→ That means f(x) is not in the form of the quadratic function

∴ f(x) is not in the form of the quadratic function above

∴ f(x) does not represent a quadratic function

∴ f(x) is not a quadratic function

∵ g(x) = 500x² + 345x

∴ The greatest power of x is 2

→ That means g(x) is in the form of the quadratic function above

∵ g(x) is in the form of the quadratic function above, where a = 500,

b = 345, and c = 0 (constant values)

∴ g(x) represents a quadratic function

∴ g(x) is a quadratic function

3 0

3 years ago

Solve and check please help ty

raketka [301]

so wt's the question of this pic?

5 0

3 years ago

A square has a diagonal with the length of 8V7 inches. What is the length of the<br> sides?

Nikitich [7]

Answer:

approximately 13.9 inches

Step-by-step explanation:

That's 8√6, not 8V7.

The four sides are of the same length (x). According to the Pythagorean Theorem, x² + x² = (diagonal length)² = (8√6)², or

2x² = 64(6) = 384

Dividing both sides by 2, we get:

x² = 192, or x² = 4(48). Then the side length is x = √16√12, or

x = 4√4√3 = 8√3. This is approximately 13.9 inches.

4 0

2 years ago

For the polynomial function ƒ(x) = x4 −25x2, find the zeros. Then determine the multiplicity at each zero and state whether the

AfilCa [17]

<u>ANSWER</u>

The zeros are $x=-5,x=0,x=5$

EXPLANATION

Given;

$f(x)=x^4-25x^2$ .

We can rewrite the function as

$f(x)=x^2(x^2-25)$

$\Rightarrow f(x)=x^2(x^2-5^2)$

$\Rightarrow f(x)=x^2(x-5)(x+5)$

The zeros are found by equating the function to zero.

$\Rightarrow x^2(x-5)(x+5)=0$

$\Rightarrow (x-5)=0$

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is $x=5$

$\Rightarrow (x+5)=0$

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is $x=-5$

$\Rightarrow x^2=0$

This last root has a multiplicity of 2.

That is

$x=0$ repeats two times.

Since the multiplicity is even, the graph touches the x-axis at the point $x=0$ .

See graph.

5 0

3 years ago