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weqwewe [10]
3 years ago
11

Nine times the input minus seven is equal to the output. If the input is -1, what is the output?

Mathematics
2 answers:
oee [108]3 years ago
6 0

9x-7 =y

9(-1) -7 =y

-16 =y

Choice A

denis23 [38]3 years ago
5 0

Answer:

(A) -16 is your answer

Step-by-step explanation:

let input = x, output = y

When x = -1

9(x) - 7 = y   (is your equation)

Plug in -1 for x

9(-1) - 7 = y

Simplify. First, multiply 9 with -1

9(-1) = -9

Next, combine like terms

-9 - 7 = y

-16 = y

(A) -16 is your answer

~<em>So Shines a Good Deed in a Weary World</em>

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Ten less than 5 times the value of a number is equal to 10 times the quantity of
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Answer:

52

Step-by-step explanation:

given that the number is a

The expression for Ten less than 5 times the value of a number is given by

5a - 10

10 times the quantity of  12 more than one-fourth of the number.

a/4 is one-fourth  of number

12 more than one-fourth of the number

a/4 + 12

expression for  10 times the quantity of  12 more than one-fourth of the number. is given by

10(a/4 + 12) = 10a/4 + 12*10 = 2.5a + 120

Given that the above two expression are equal

equating them we have

5a - 10 = 2.5a + 120

adding 10 both sides

=>5a - 10+ 10  = 2.5a + 120 + 10

=> 5a = 2.5a + 130

subtracting 2.5a from both sides

=> 5a - 2.5a = 2.5a + 130 - 2.5a

=> 2.5a = 130

dividing both side by 2.5

=> a = 130/2.5 = 52

Thus, value of a is 52

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3 years ago
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The swimming pool and the floor of your gym are similar in size. The pool is 75 feet long by 60 feet wide. What are possible dim
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Divide 81 ft in the ratio 5 :4
Mumz [18]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B2%7D%7B15y%7D%20%20%2B%20%20%5Cfrac%7B3%7D%7B5y%20%7B%7D%5E%7B3%7D%20%7D" id="
Xelga [282]

Answer:

2y²   +   9

---------------

      15y³

Step-by-step explanation:

Start by identifying the LCD, and then change each fraction so that its denominator is the LCD.

Here the LCD is 15y³, which is evenly divisible by 15y and 5y³.

Focus now on the first fraction:  2 / (15y).  Multiplying numerator and denominator of this fraction by y² results in

y²·2          2y²

--------- → ----------

y²·15y       15y³           ←This is the correct LCD

Multiplying numerator and denominator of the second fraction by 3 results in:

   3·3            9

------------ → ---------

 3·5y³         15y³          ←This is the correct LCD

So now those two original terms look like:

 2y²         9

--------- + --------

 15y³       15y³

and this can be written in simpler form as:

2y²   +   9

---------------

      15y³

3 0
3 years ago
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