Answer:
A
Step-by-step explanation:
It goes up and down due to the x^3 then the 3x^2
For this case we have the following expression:
We apply distributive property:
We rewrite in equivalent form:
Answer:
Any line parallel to the given line will have the same slope as does the given line. Here that slope is -9.
The new line passes thru (-2,5).
Therefore, using the slope-intercept form,
5 = -9(-2) + b. Find b: 5 = 18 + b, so b = -13. The equation of the new, parallel line is then
y = -9x - 13 (answer to first question).
If you want the slope of a line perpendicular to the given line, use the "negative reciprocal" of the slope of the given line as the slope of the new, perpendicular line. Thus, the new slope will be -1/(-9), or (+1/9).
Use the slope-intercept form, with slope = (1/9), to find the line perpendicular to the given line that passes thru the given point. Share your work, please.
Answer:
<u> 2y + 3x = 3</u>
Step-by-step explanation:
The standard form of equation of a line is expressed as;
y = mx+c
m is the slope
b is the intercept
We are to find the equation of a line passing through the points (-3,19) and (6,-2)
First get the slope
m = y2-y1/x2-x1
m = -2-19/6-(-3)
m = -21/9
m = -7/3
Get the y- intercept b;
Substitute the coordinate (6, -2) and m = -7/3 into the expression y = mx+b and get b;
-2 = -7/3(6) + c
-2 = -7/2 + c
c = 7/2 - 2
c = (7-4)/2
c = 3/2
Substitute the slope and intercept into the formula
y = mx+b
y = -7x/2 + 3/2
Multiply through by 2;
2y = -7x + 3
2y + 7x = 3
Hence the required equation is<u> 2y + 7x = 3</u>
Here you go. Gffghgftyhvv