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Soloha48 [4]
2 years ago
15

How many decimal places are in the product of 1.91 and 2.3?

Mathematics
2 answers:
san4es73 [151]2 years ago
8 0

Answer:

3

Step-by-step explanation:

2+1 = 3

Dahasolnce [82]2 years ago
8 0

Answer:

3

Step-by-step explanation:

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This is the first step in which construction?
slavikrds [6]

Answer:

Option A is correct.

Step-by-step explanation:

The first step in the construction of a square inscribed in a circle is to draw a diameter of the circle.

Then we have to draw perpendicular bisector of the diameter using a compass.

Therefore, the perpendicular bisector will be another diameter of the circle and both the diameters will meet at the center of the circle.

Now, join the points with straight lines in order where the two diameters meet the circle. And finally, we will get a square inscribed in the circle.

Hence, option A is correct. (Answer)

5 0
3 years ago
you have a right angle triangle, that is labelled with A B and C. The hypotenuse is 2.1 km and point C's angle is 57. Is AB or A
LUCKY_DIMON [66]

Answer:

ab

Step-by-step explanation:

ac should always be longer for it would be the hypotnuse

7 0
3 years ago
If a cookie weighs
m_a_m_a [10]
1 cookie = 3/4 of an ounce

16 cookies = ?

3/4 x 16 = 12

16 cookies = 12 ounces

24 packages = ?

12 x 24 = 288

24 packages = 288 ounces of cookies.

So, your final answer is 288 ounces.

I hope this helps! Good luck!
5 0
3 years ago
Read 2 more answers
A circular rug has a radius of 3 ft. What is the circumference of the rug? Use 3.14 for Pi.
LenaWriter [7]

Answer:

18.84 ft

Step-by-step explanation:

2*3.14*3=18.84 ft

7 0
2 years ago
Find the length of diagonal HJ. Round to the nearest hundredth.
Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}, where

 (x_{1},y_{1}) and (x_{2},y_{2}) are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ x_{1}=-4 and x_{2}=5

∴ y_{1}=3 and y_{2}=-3

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = \sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}

∴ HJ = \sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

7 0
3 years ago
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