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ludmilkaskok [199]
3 years ago
12

Each person in a ticket line gets either one or two tickets. You are the 51st person in line. Forty percent of the people in fro

nt of you get one ticket each, and the rest of the people in front of you get two tickets each. How many tickets will have been given out when you reach the ticket booth?
Mathematics
1 answer:
Marrrta [24]3 years ago
5 0
80 tickets have been given out

50*.4=20
50*.6=30
30*2=60
60+20=80
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Answer:

The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes

Step-by-step explanation:

We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 35 - 1 = 35

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.975([tex]t_{975}). So we have T = 2.0322

The margin of error is:

M = T*s = 2.0322*30 = 60.97

The upper end of the interval is the sample mean added to M. So it is 204 + 60.97 = 264.97

The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes

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3 years ago
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