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ludmilkaskok [199]
3 years ago
12

Each person in a ticket line gets either one or two tickets. You are the 51st person in line. Forty percent of the people in fro

nt of you get one ticket each, and the rest of the people in front of you get two tickets each. How many tickets will have been given out when you reach the ticket booth?
Mathematics
1 answer:
Marrrta [24]3 years ago
5 0
80 tickets have been given out

50*.4=20
50*.6=30
30*2=60
60+20=80
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Answer:

B 12.68

Step-by-step explanation:

you will need to find the distance between each segment-

so the length of DC, CF, FE, ED

d=\sqrt{(x_{2}-x_{1})  ^{2}+(y_{2}-y_{1})  ^{2}  }

DC:

D(-2,-1) C(-1,2)

d=\sqrt{(-1--2)^{2} +(2--1)^{2} } \\d=\sqrt{1^{2}+3^{2}  } \\d=\sqrt{10} =3.16

CF:

C(-1,2) F(1,1)

d=\sqrt{(1--1)^{2} +(1-2)^{2} } \\d=\sqrt{2^{2}+-1^{2}  } \\d=\sqrt{4+1} \\d=\sqrt{x} 5=2.24

FE

F(1,1) E(2,-2)

d=\sqrt{(2-1)^{2} +(-2-1)^{2} } \\d=\sqrt{1^{2} +(-3)^{2} } \\d=\sqrt{1+9} \\d=\sqrt{10}= 3.16

ED

E(2,-2) D(-2,-1)

d=\sqrt{(-2-2)^{2} +(-1--2)^{2} } \\d=\sqrt{(-4)^{2}+1^{2}  } \\d=\sqrt{16+1} \\d=\sqrt{17}= 4.12\\

3.16+2.24+3.16+4.12= 12.68

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The after-school basketball league has 35 seventh-graders and 15 eighth-graders. What percent of the after-school basketball pla
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The answer is 30%. This is my work below

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Each pair of shapes is congruent. Identify a transformation or sequence of transformations that could take one
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When one shape can become another using only Turns, Flips and/or Slides, then the two shapes are Congruent. Two shapes are Similar when we need to Resize for one shape to become another (we may also Turn, Flip and/or Slide). So, when one shape can become another using transformation, the two shapes might be Congruent or just Similar?

Step-by-step explanation:

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The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in
Stolb23 [73]

Answer:

ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=34.5 represent the sample mean

\mu population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=300-1=299

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that t_{\alpha/2}=1.653

And the margin of error is given by:

ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75

±0.75 ounce

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