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DochEvi [55]
3 years ago
12

Jason rolls the die 14 times. What is the experimental probability that he will roll a 2

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0
There’s 14 rolls. The probability he lands on a 2 would be 2/14. Once you simplify it it would give you a probability of 1/7
You might be interested in
Solve the right triangle. Round decimals to the nearest tenth
Tems11 [23]

Answer:

  j = 19.6

  k = 25.9

  J = 49°

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relationships between sides and angles in a right triangle.

<h3>Analysis</h3>

The given side is opposite the given angle. We want to find the other acute angle and the missing sides: the hypotenuse, and the adjacent side. The relations involving the opposite side are ...

  Sin = Opposite/Hypotenuse   ⇒   Hypotenuse = Opposite/Sin

  Tan = Opposite/Adjacent   ⇒   Adjacent = Opposite/Tan

Of course, the acute angles in a right triangle are complementary, so we can use that fact to find the missing angle.

<h3>Application</h3>

  Hypotenuse = Opposite/Sin

  IJ = 17/sin(41°) ≈ 25.9

  Adjacent = Opposite/Tan

 IK = 17/tan(41°) ≈ 19.6

  Angle J = 90° -41° = 49°

In summary, ...

  j = 19.6

  k = 25.9

  J = 49°

8 0
2 years ago
Please help with this question its in the picture :)
s2008m [1.1K]

Step-by-step explanation:

A

6 0
3 years ago
Read 2 more answers
33. What is the value of x when x + 10 = 4?<br> A. -14<br> B. -6<br> C. O<br> D. 6
SCORPION-xisa [38]

Answer:

B. -6

Step-by-step explanation:

-6 + 10 =4

7 0
3 years ago
Read 2 more answers
3 times a number is 54 less than the square of that number. Find the negative solution.
son4ous [18]

Answer:

-6

Step-by-step explanation:

3n = n² - 54

n² - 3n - 54 = 0

n² - 9n + 6n - 54 = 0

n(n - 9) + 6(n - 9) = 0

(n - 9)(n + 6) = 0

n = 9 , -6

5 0
3 years ago
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
3 years ago
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