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3 years ago

Does anyone know how to calculate 4 to the -3 power?

Mathematics

2 answers:

Fofino [41]3 years ago

7 0

Answer:

0.015625

Step-by-step explanation:

4^-3 = 0.015625

Stells [14]3 years ago

5 0

Answer:

Step-by-step explanation:

4^(-3) = 1/4^3 = 1/(4*4*4) = 1/64

which can also be written as 1/(2^6)

depending on your answer options.

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Can someone help me

Komok [63]

$114.6 \times .066 = 7.5636 \\ 8$
I'm not sure if this is right. I didn't feel confident with my answer.

6 0

3 years ago

Hi there it's me again! Sorry to bother you, but can someone help me out with this?

stiv31 [10]

Answer:

hey,

your answer Is 1. :)

Step-by-step explanation:

no matter how many lines we try to draw which pass thru broh A and B, there would just be 1 straight line passing thru both points A and B.

I didn't do the activity tho

you can use a plain sheet of paper as a plane. and draw points A and B on it and then connect them drawing a straight line from A to B.

4 0

3 years ago

Graph each equation y=7x-7<br><img src="https://tex.z-dn.net/?f=y%20%3D%207x%20-%207" id="TexFormula1" title="y = 7x - 7" alt="y

Dafna1 [17]

to graph a LINEar equation, since it's just a straight line, recall, to draw a straight line all you need is two points.

so we can just pick two random "x" values, hmmmmm say x = 0, what's "y"?

y = 7(0)-7 => y = -7....................................... so that gives us the point (0, -7)

hmmm x = 2, what is "y"?

y = 7(2) - 7 => y = 14-7 => y = 7................. so we get the point (2, 7).

then just plot those, and run a line through them.

6 0

3 years ago

Simplify 18 - 2[X + (x - 5)].<br> 8- 4x<br> 28 - 4x<br> 28 - 2x

malfutka [58]

Answer:

28 - 4x

Step-by-step explanation:

$18 -2 [x + (x - 5)] \\ = 18 - 2 [x + x - 5] \\ = 18 - 2 [2x - 5] \\ = 18 -4x + 10 \\ = 28 - 4x \\$

5 0

4 years ago

A worker on a scaffolding 75 ft above the ground needs to lift a 500 lb bucket of cement from the ground to a point 30 ft above

Lemur [1.5K]

Answer:

W = 15900 ft.lb

Step-by-step explanation:

From the given information.

Consider y to be the distance from the ground towards the bucket of the cement.

At height y, suppose the bucket is lifted by Δy.

Then, the workdone can be = 500Δy + 0.5(75 - y) Δy

where;

The bucket of the cement = 500Δy

The remaining of the rope = 0.5(75 - y) Δy

However; the workdone (W) can be calculated as:

$W = \int^{30}_{0} \ 500 \ dy + \int^{30}_{0} \ 0.5 (75-y ) \ dy$

$W = 500 \times 30 + 0.5 \bigg(75 \times 30 - \dfrac{1}{2} \times 30^2 \bigg )$

W = 15000 + 0.5 ( 2250 - 450)

W = 15000 + 900

W = 15900 ft.lb

6 0

3 years ago