Question

HELP PLEASE !!! If anybody sees this can you help me ASAP

Answer 1

$g(x)=(x-3)^{2} +2$ has the same shape as the parabola $g(x)=x^{2}$ but with vertex shifted to (3, 2).

The vertex of the parabola $(y-k)^{2} =4a(x-h)$ is (h, k).

Equation of the given graph is $g(x) = (x-3)^{2} +2$

Subtract 2 from both sides.

$g(x)-2=(x-3)^{2}$

Hence, its vertex is at (3, 2).

Please find the attached graph.