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andrey2020 [161]
3 years ago
5

Pls help ASAP ummmmmmmm

Mathematics
1 answer:
LekaFEV [45]3 years ago
3 0

c costs the least

Hope this helps :)

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PLEASE ANSWERRRRRRRRRRRRRRRRRRRRRRR
Paul [167]

Answer:

c

Step-by-step explanation:

just cause

8 0
3 years ago
Which of the following are factors of x^4 – 16? Select all that apply.
nekit [7.7K]

<h2><em>Answer:</em></h2><h2><em>x^</em><em>2</em><em>+</em><em>4</em><em> </em><em>and </em><em>X+</em><em>2</em></h2>

<em>Solution,</em>

<em>x^</em><em>4</em><em>-</em><em>1</em><em>6</em>

<em>=</em><em> </em><em>(</em><em>X^</em><em>2</em><em>)</em><em>^</em><em>2</em><em>-</em><em>(</em><em>4</em><em>)</em><em>^</em><em>2</em>

<em>Use </em><em>the </em><em>formula(</em><em>a^</em><em>2</em><em>-</em><em>b</em><em>^</em><em>2</em><em>)</em>

<em>=</em><em> </em><em>(</em><em>x^</em><em>2</em><em>+</em><em>4</em><em>)</em><em>(</em><em>x^</em><em>2</em><em>-</em><em>4</em><em>)</em>

<em>=</em><em>(</em><em>x^</em><em>2</em><em>+</em><em>4</em><em>)</em><em>(</em><em>x^</em><em>2</em><em>-</em><em>2</em><em>^</em><em>2</em><em>)</em>

<em>=</em><em>(</em><em>x^</em><em>2</em><em>+</em><em>4</em><em>)</em><em>(</em><em>X+</em><em>2</em><em>)</em><em>(</em><em>x-2)</em>

<em>Hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

5 0
3 years ago
Read 2 more answers
DO IT ASAP! Thank you very much!
frozen [14]

Answer:

a = 5

Step-by-step explanation:

According to the factor theorem, if x + 2 is a factor, then by dividing the polynomial by the binomial, we are meant not to have a remainder

In this case, the remainder would be zero

So, if we set the binomial equals zero and substitute the x-value into the polynomial, we are supposed to have 0

So we have this as;

x + 2 = 0

x = -2

-2^3 -2(-2)^2 -2(a) + 6 = 0

-8-8-2a + 6 = 0

-16 + 2a + 6 = 0

2a -10 = 0

2a = 10

a = 10/2

a = 5

3 0
3 years ago
The double box plot shows the test scores for Miss Robinson's second and fourth period
Gennadij [26K]
We can’t see the box plot?
4 0
3 years ago
The sum of three numbers is 26. Twice the first minus the second is the third less 2. The third is the second minus 3 times the
Agata [3.3K]

Let a, b, c represent the three numbers. The problem statement gives rise to three equations:

  • a +b +c = 26
  • 2a -b = c -2
  • -3a +b = c

Adding the first two equations gives

... (a +b +c) +(2a -b) = (26) +(c -2)

... 3a +c = 24 +c . . . . . simplify

... 3a = 24 . . . . . . . . . . subtract c

... a = 8 . . . . . . . . . . . . divide by 3

Adding the second and third equations gives ...

... (2a -b) +(-3a +b) = (c -2) +(c)

... -a = 2c -2 . . . . simplify

... -6 = 2c . . . . . . add 2, substitute for a

... -3 = c . . . . . . . . divide by 2

Using the third equation we can find b.

... -3·8 +b = -3 . . . . substitute for a and c

... b = 21 . . . . . . . . .add 24

The numbers are 8, 21, -3.

_____

The method above is sort of "ad hoc", taking advantage of the numbers in this particular set of equations. You can use more formal methods of Gaussian elimination or Cramer's Rule to solve these by just following a procedure. Or, your graphing calculator can do it for you.

6 0
3 years ago
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