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victus00 [196]
3 years ago
15

If the hypotenuse of an isosceles right triangle is 12 cm what are the measurements of the legs

Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0
That is a 45 45 90 triangle.
In such a triangle, the legs equal the hypotenuse divided by sq root (2)
So, each leg = 12 / <span> <span> <span> 1.4142135624 </span> </span> </span>
which equals <span> <span> <span> 8.4852813742 </span> </span> </span>
or about 8.5 cm

Source:
http://www.1728.org/trig2.htm


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Initially a tank contains 10 liters of pure water. Brine of unknown (but constant) concentration of salt is flowing in at 1 lite
zhenek [66]

Answer:

Therefore the concentration of salt in the incoming brine is 1.73 g/L.

Step-by-step explanation:

Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.

Let the concentration of salt  be a gram/L

Let the amount salt in the tank at any time t be Q(t).

\frac{dQ}{dt} =\textrm {incoming rate - outgoing rate}

Incoming rate = (a g/L)×(1 L/min)

                       =a g/min

The concentration of salt in the tank at any time t is = \frac{Q(t)}{10}  g/L

Outgoing rate = (\frac{Q(t)}{10} g/L)(1 L/ min) \frac{Q(t)}{10} g/min

\frac{dQ}{dt} = a- \frac{Q(t)}{10}

\Rightarrow \frac{dQ}{10a-Q(t)} =\frac{1}{10} dt

Integrating both sides

\Rightarrow \int \frac{dQ}{10a-Q(t)} =\int\frac{1}{10} dt

\Rightarrow -log|10a-Q(t)|=\frac{1}{10} t +c        [ where c arbitrary constant]

Initial condition when t= 20 , Q(t)= 15 gram

\Rightarrow -log|10a-15|=\frac{1}{10}\times 20 +c

\Rightarrow -log|10a-15|-2=c

Therefore ,

-log|10a-Q(t)|=\frac{1}{10} t -log|10a-15|-2 .......(1)

In the starting time t=0 and Q(t)=0

Putting t=0 and Q(t)=0  in equation (1) we get

- log|10a|= -log|10a-15| -2

\Rightarrow- log|10a|+log|10a-15|= -2

\Rightarrow log|\frac{10a-15}{10a}|= -2

\Rightarrow |\frac{10a-15}{10a}|=e ^{-2}

\Rightarrow 1-\frac{15}{10a} =e^{-2}

\Rightarrow \frac{15}{10a} =1-e^{-2}

\Rightarrow \frac{3}{2a} =1-e^{-2}

\Rightarrow2a= \frac{3}{1-e^{-2}}

\Rightarrow a = 1.73

Therefore the concentration of salt in the incoming brine is 1.73 g/L

8 0
3 years ago
Michael consumes a 16-ounce bag of potato chips and 12-ounce bag of pretzels every day after school. How many more ounces of pot
Paladinen [302]

Every day, Michael consumes 4 more ounces than the pretzels. Multiply 5 by 4 to recieve the answer:

4 x 5 = 20

So the answer is A.

7 0
2 years ago
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Suppose that the number of bacteria in a certain population increases according to an exponential growth model. A sample of 2600
melisa1 [442]

Answer: There is 3.994% continuous growth rate per hour.

Step-by-step explanation:

Since we have given that

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After two and a half hours,

Number of bacteria = 2873

We need to find the continuous growth rate per hour.

As we know the equation for continuous growth rate per hour.

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Hence, there is 3.994% continuous growth rate per hour.

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The answer is:
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Sam has $42,000 one year after graduating. So when he graduates, he would have $38000.

Hope this helps!

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Which of the following solutions solves the system?
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The answer is C

(1,-1)
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