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Kipish [7]
3 years ago
6

Designer Dolls, Inc. found that the number N of dolls sold varies directly with their advertising budget A and inversely with th

e price P of each doll. The company sold 5200 dolls when $26,000 was spent on advertising and the price of a doll was set at $30. Determine the number of dolls sold when the amount spent on advertising is increased to $52,000. Round to the nearest whole number.. . A. 5,200 dolls. . B. 1,723 dolls. . C. 3,447 dolls. . D. 10,400 dolls
Mathematics
2 answers:
Travka [436]3 years ago
7 0

Answer:

D


Step-by-step explanation:

Direct Variation takes the form  A = kB  

Inverse Variation takes the form  A=k(\frac{1}{B})

  • Where A and B are the 2 variables associated and k is the proportionality constant.

<em>Since </em><em>number of dolls [N] </em><em>varies </em><em>directly </em><em>with </em><em>advertising budget [A],</em><em> in our equation, </em><em>A should go in the numerator</em><em> and since </em><em>number of dolls [N] </em><em>varies </em><em>inversely</em><em> with </em><em>price of dolls [P]</em><em>, </em><em>P should go in the denominator.</em>

Thus we can write our equation as:

N=k(\frac{A}{P})

Solving this equation for k given the information "The company sold 5200 dolls when $26,000 was spent on advertising and the price of a doll was set at $30":

N=k(\frac{A}{P})\\5200=k(\frac{26,000}{30})\\5200=k(866.67)\\k=\frac{5200}{866.67}=5.99

Rounding k=5.99 to k=6


Now, given that we want to find the number of dolls [N] when A=52,000  and  P=30 , we have:

N=(6)(\frac{52,000}{30})\\N=10,400 dolls

Answer choice D is correct.


RoseWind [281]3 years ago
6 0
The correct answer among all the other choices is D. 10,400 dolls. This is the number of dolls sold when the amount spent on advertising is increased to $52,000. Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help. 
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