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lbvjy [14]
3 years ago
6

Allen wants to have a mean of 90 on his math quizzes. So far, he has scored 86, 94, 88, 95, and 89. What is the least score that

Allen needs on his next quiz to have a mean of 90?
Mathematics
1 answer:
viva [34]3 years ago
3 0

Answer:

88

Step-by-step explanation:

\frac{86 + 94 + 88 + 95 + 89 + x}{6}  = 90

The mean would be the sum of all the math quiz grades divided by the number of quizzes taken.

Solve for x:

86 + 94 + 88 + 95 + 89 + x = 540

452 + x = 540

x = 88

Thus, Allen needs at least an 88 to obtain a mean of at least 90.

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Mike collected milk from 3 of his cows at the dairy farm. from the first cow, he collected 4/5 gallon of milk. the second cow pr
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Answer:

(A) 2 3/10

(B) 1 7/15

Step-by-step explanation:

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According to the Bureau of Labor Statistics, citizens remain unemployed for an average of 15.9 weeks before finding their next j
Ahat [919]

Complete Question

According to the Bureau of Labor Statistics, citizens remain unemployed for an average of 15.9 weeks before finding their next job (June, 2008). Suppose you want to show that Louisiana has been effective in getting their unemployed back to work sooner. You take a random sample of 50 citizens who were unemployed six months earlier and ask them to report the duration. You find that the average time spent unemployed was 13.4 weeks with a sample standard deviation of the time unemployed is 6.7 weeks.

1 Which of the following statements is the correct alternative hypothesis?

2 The test statistic for testing the hypothesis is

a. -2.64

b. -2.32

c. -2.11

d. -1.28

e. none of these are correct

Answer:

1  

 The  alternative hypothesis  H_a  :  \mu < 15.9

2

The  test statistics z =  -2.64  

Step-by-step explanation:

From the question we are told that

     The population  mean value for time  citizens remain unemployed is  \mu  =  15.9 \  weeks

     The  sample size is  n =  50

     The  sample standard deviation is  6.7 weeks.

      The  sample mean value for time  citizens remain unemployed is  \mu  =  15.9 \  weeks

       

     The  null hypothesis is  H_o  :  \mu \ge 15.9

      The  alternative hypothesis  H_a  :  \mu < 15.9

Generally test statistics is mathematically represented as

       z =  \frac{ \= x  - \mu }{ \frac{s}{\sqrt{n} } }  

=>    z =  \frac{13.4 - 15.9}{\frac{6.7}{\sqrt{50}}}

=>     z =  -2.64  

   

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