Answer:
Word: Two hundred ninety-three thousand, eight hundred five.
Expanded: 200,000 + 90,000 + 3,000 + 800 + 5
hope this helps!(Please give brainliest)
We have a triangle with sides a=2.4 m, b=3.2 m and c=4.6 m and angle A=110° between the rope a and b. To find the angle A we can use the the law of cosines:
c²=a²+b²-2*a*b*cosA.
Here we solve for cosA:
c²-a²-b²=-2*a*b*cosA
cosA=(c²-a²-b²)/-2*a*b=-0.336, now we take the inverse cosine:
cos⁻¹(cosA)=cos⁻¹(-0.336) and get:
A=109.62° which is very close to 110°.
So the correct answer is: we need the law of cosines to solve for angle A.
x³+2x²-6x-12=x²•(x+2)-6(x+2)=(x+2)•(x²-6)
Answer:
Question 1: seems all A,B and C are incorrect
Question 2: long = 45/(3*3) =45/9 =5
20+12+15= 32+15 = 47 minutes in total
300 meters per minute
300 * 47 = 14100 meters in total
with this we can see the first race was 4/9 that distance meaning the first race was 6266.6 meters long
14100 - 6266.6 = 7833.3
2/5 of 7833.3 is 3133.32
therefore 7833.3 - 3133.32 will give the distance of the third part of the race
meaning of course the answer is 4699.98 or rounding up 4700 meters for the third race