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3 years ago

If I have a Pentagon shape and it's 33 centimeters long, what would be my Perimeter?

Mathematics

1 answer:

Oksana_A [137]3 years ago

4 0

The answer is 165. If you add 33 five times you get 165. Or you could do what i did and do 33 times 5.

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Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

Find the area of the following figure.

Zigmanuir [339]

Answer:

312

Step-by-step explanation:

Triangles

1/2 12 *10 = 6*10 = 60

there are two triangles meaning we have to multiply 60 by 2 = 120

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3 years ago

Which figures can be circumscribed by a circle? Select all that apply.

Darina [25.2K]

Answer:

A, B, C, D

Step-by-step explanation:

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2 years ago

Read 2 more answers

A rectangle swimming pool is 8 feet deep. One side of the pool is 4.5 times longer than the other. The amount of water needed fo

wel

The side lengths of the pool 10 ft and 45 ft.

<u>SOLUTION: </u>

Given, a rectangle swimming pool is 8 feet deep.

One side of the pool is 4.5 times longer than the other.

Let the length of pool be n feet, the width will be 4.5n feet

The amount of water needed for the swimming pool is 3600 cubic ft

We have to find the dimensions of the pool. Now, we know that,

$\begin{array}{l}{\text {volume of pool}=\text {depth} \times \text {length } \times \text {width}} \\\\ {\rightarrow 3600 \text { cubic } f t=8 \text { feet } \times \text { n feet } \times(4.5 n) \text { feet }} \\\\ {\rightarrow 8 n \times 4.5 n=3600} \\\\ {\rightarrow 36 n^{2}=3600} \\\\ {\rightarrow n^{2}=100}\end{array}$

On taking square root on both sides we get,

$\begin{array}{l}{\rightarrow\sqrt{n^{2}}=\sqrt{100}} \\\\ {\rightarrow n=10 \mathrm{ft}}\end{array}$

So, the width will be $4.5 n=4.5 \times 10=45 \mathrm{ft}$

5 0

3 years ago