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weqwewe [10]
3 years ago
13

Wendy is concentrating a sample by distillation. She started with 140 mi of a solution that was about 0.07% inorganic salts. Aft

er several hours of distillation, the amount of inorganic salts hasn't changed ,but the volume has decreased to 48 ml. What percent of the solution after distillation is in organic salts?
Mathematics
1 answer:
pantera1 [17]3 years ago
6 0
The percentage of solution o after distillation 36%
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Find the Perimeters of the rectangle whale<br>degonal is 5cm and lenght is 4cm ​
amid [387]

Answer:

14

Step-by-step explanation:

First, we have to get the breadth value.

By the pythagoras theoreom,

Diagonal²=length² + breadth²

breadth = √( Diagonal²- length²)

breadth = √( 5² - 4²)

breadth = √9

breadth= 3

Perimeter of a rectangle = 2x ( length + breadth)

                                         = 2 x (  4 + 3)

                                         = 2 x 7

                                         = 14

3 0
3 years ago
What is the least common denominator for 2/5 + 3/7
muminat

Answer:

35

Step-by-step explanation:

2/5 + 3/7

the least common denominator is 35 because 14/35 + 15/35.

3 0
3 years ago
Read 2 more answers
The graph of a quadratic function contains (4,-64) and it's vertex is at the origin.write an equation for this function.
lesya692 [45]

Answer:

Step-by-step explanation:

Not sure what form you need this in, but it really doesn't matter, as you'll see in the final equation.  I used the vertex form and solved for a:

y=a(x-h)^2+k

We are given the vertex (h, k) as the origin (0, 0), and we have a point that the graph goes through as (4, -64).  That's our x and y.  Plugging in what we have:

-64=a(4-0)^2+0 gives us

-64 = 16a and

a = -4.  That means that the quadratic equation is

y=-4x^2  which is both vertex form and standard form here, no difference.

5 0
3 years ago
PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM
Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

c^{2} =a^{2} +b^{2}

c = \sqrt{a^{2} +b^{2} }

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = \sqrt{40^{2} + 9^{2} }

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = \sqrt{12^{2} + 13^{2} }

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

35^{2} = 20^{2} + b^{2}

1225 = 400 + b^{2}

b^{2} = 1225 - 400

b^{2} = 825

\sqrt{b^{2} } = \sqrt{825}

b = 5 \sqrt{33}

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

37^{2} = 20^{2} + b^{2}

1369 = 400 + b^{2}

b^{2} = 1369 - 400

b^{2} = 969

Taking square root on both sides

b = 31.12

Hope it helps.

4 0
3 years ago
Sec (of theta)=25/24<br> find cot(of theta)
Len [333]
If secant of theta = <span> <span> <span> 1.0416666667 </span> </span> </span> then
theta = 16.26 Degrees
cotangent of theta = 3.4286



4 0
3 years ago
Read 2 more answers
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