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weqwewe [10]
3 years ago
13

Wendy is concentrating a sample by distillation. She started with 140 mi of a solution that was about 0.07% inorganic salts. Aft

er several hours of distillation, the amount of inorganic salts hasn't changed ,but the volume has decreased to 48 ml. What percent of the solution after distillation is in organic salts?
Mathematics
1 answer:
pantera1 [17]3 years ago
6 0
The percentage of solution o after distillation 36%
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Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

  • There are 100 students
  • 65 are members of a mathematics club
  • 40 are members of a physics club
  • 10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

  club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

Learn more:

You can learn more about word problems in brainly.com/question/8907574

#LearnwithBrainly

5 0
3 years ago
Two planes are flying away from Toronto Pearson International Airport. The Air Canada
erica [24]

Answer:

1832 miles

Step-by-step explanation:

First we need to find the angle between the routes of the planes.

If one is N30°W and the other is S45°W, we can find the angle between the routes with the following equation:

30 + angle + 45 = 180

angle = 105°

Then, we need to find the distance travelled by each plane, using the formula:

distance = speed * time

The time is 1.5 hours, so we have that:

distance1 = 800 * 1.5 = 1200 km

distance2 = 750 * 1.5 = 1125 km

Now, to find the distance between the planes, we can use the law of cosines:

distance^2 = 1200^2 + 1125^2 - 2*1200*1125*cos(105)

distance^2 = 3356214.43

distance = 1832 miles

5 0
3 years ago
What is 3 equivalent ratios for 2/6
Crazy boy [7]
1/3
3/9
4/12
are equivalent to 2/6
3 0
3 years ago
Part 2 of the other question and obvi the ones that are crossed out, you do not have to do.
zavuch27 [327]

Answer:

19)51.06

22)-3.08

25) 19.25 cost per visit.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
I need help please!!!
Setler79 [48]
Do you need help with the whole worksheet ?
4 0
2 years ago
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