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lana66690 [7]
3 years ago
15

PLEASE HELP!!!

Mathematics
1 answer:
rosijanka [135]3 years ago
8 0

Answer:

Area of the other polygon = 4 in.²

Step-by-step explanation:

Area of the bigger polygon : Area of the smaller polygon = square of the side length of the bigger polygon : square of the corresponding side length of the smaller polygon

Let "x" represent the area of the smaller polygon

Thus, we have:

100/x = 20²/4²

100/x = 400/16

100/x = 25

Cross multiply

25x = 100

Divide both sides by 25

25x/25 = 100/25

x = 4

Area of the other polygon = 4 in.²

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Answer:

\cos\theta=\frac{10}{\sqrt{116}}

Step-by-step explanation:

To solve this, we can imagine a line drawn directly down from the point (10,4) to the x-axis. This would make a right triangle with length 10 and height 4.

\cos\theta is equal to the length of adjacent leg to the angle divided by the length of the hypotenuse of the triangle. From the picture, we can see the adjacent leg is 10.

We can use Pythagorean's Theorem to find the hypotenuse (let c represent the length of the hypotenuse):

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Thus, we know the adjacent is 10, and the hypotenuse is \sqrt{116}. This means \cos\theta=\frac{10}{\sqrt{116}}.

Hope this helps!

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Step-by-step explanation:

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