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iris [78.8K]
3 years ago
15

Points that lie on the function h(x) = 3x 2

Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0

Answer:

To see all the points that lie on the equation

h(x) = 3*x^2

We use a graphing calculator, to plot the function h(x)

Please see attached image for more information.

We can see in red all the points  that lie on the function. There are an infinite number of points in it.

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A sphere has a radius of 3m. Calculate its surface area and round to the nearest hundredth for your final answer.
bonufazy [111]

Answer:

B

Step-by-step explanation:

formula   s =4*pi*r^2

s=4(3.14)(3^2)

s = 12.56(9)s= 113.04

5 0
4 years ago
In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.
Hitman42 [59]

\longmapstoThe value of "x" is 5.

\large\underline{\sf{Solution-}}

Given that,

A trapezium ABCD in which AB || CD such that

  • AO = x - 1

  • CO = BO = x + 1

  • OD = x + 4

Now,

\rm In \: \triangle  \: AOB  \: and \: \triangle \:  COD

\rm  \: \angle  \: AOB  \: and \: \angle \:  COD \:  \:  \{vertically \: opposite \: angles \}

\rm  \: \angle  \:ABO  \: and \: \angle \:  CDO \:  \:  \{alternate \: interior \: angles \}

\bf \: \triangle  \: AOB \:  \sim \:  \triangle  \: COD \:  \:  \:  \{AA \: similarity \}

\bf\longmapsto\:\dfrac{AO}{CO}  = \dfrac{BO}{DO}

\rm \longmapsto\:\dfrac{x - 1}{x + 1}  = \dfrac{x + 1}{x + 4}

\rm \longmapsto\:(x - 1)(x + 4) =  {(x + 1)}^{2}

\rm \longmapsto\: {x}^{2} - x + 4x - 4 =  {x}^{2} + 1 + 2x

\rm \longmapsto\: 3x - 4 =  1 + 2x

\rm \longmapsto\: 3x  -  2x=  1 +4

\bf\longmapsto \:x = 5

7 0
3 years ago
Please give me the answer<br> What is the value of the expression
natali 33 [55]

Answer:

Step-by-step explanation:

4*7+2^{4}

=28+2*2*2*2

=28+16

=44

did you not have a calculator?

4 0
3 years ago
Read 2 more answers
Determine if the Mean Value Theorem for Integrals applies to the function f of x equals the square root of x minus 1 on the inte
german

The theorem does not apply.

1. Set the function f(x)=sqrt(x-1) equal to 0 to find what values of x make f(x) defined. So:

x - 1 is < or = to 0

x > or = to 0

2.) find the values where x is defined:

x - 1 > or = to 0

x > or = to 0

Domain = all values of x that define f(x)

[1,infinity)

{x|x> or = to 1}

DNE because 1 is not in the domain because (1-1)^1/2 = 0.

4 0
3 years ago
What is the common denominator of 1/a + 1/b in the complex fraction 1/a-1/b divided by 1/a+ 1/b?
timurjin [86]

Answer:

common denominator of 1/a + 1/b is  ab

however simplifying the complex fraction gives:   (b-a)/(b +a)

Step-by-step explanation:

common denominator of 1/a + 1/b

should be the product of the denominators

a*b

so   1/a  + 1/b =   (b + a)/ab

ao

( 1/a  - 1/b)  divided by (1/a + 1/b) =  (b - a)/(ab)  divided by (b+a)/ab

8 0
4 years ago
Read 2 more answers
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