Answer:
12, 23, 48, 325
Step-by-step explanation:
So, when given two inequalities and asked to find the values that make both true, it is considered a system of equations. To solve a system of equation, you have to graph the inequalities and find where they intersect.
Inequality 1:
(-3x) + 5 < (-10)
Inequality 2:
7x + x - 4 > 28
simplifies to: 8x - 4 > 28
When graphed, the inequalities don't intersect, but rather have a similar shaded area overlapping from the point of 5 and greater.
Answers that apply from given list would be:
12, 23, 48, 325
As I look into the problem with a deeper meaning then math I realize this answer can be not as hard as it appears and it could be hard to answer it
Answer:
Probability that component 4 works given that the system is functioning = 0.434 .
Step-by-step explanation:
We are given that a parallel system functions whenever at least one of its components works.
There are parallel system of 5 components and each component works independently with probability 0.4 .
Let <em>A = Probability of component 4 working properly, P(A) = 0.4 .</em>
<em>Also let S = Probability that system is functioning for whole 5 components, P(S)</em>
Now, the conditional probability that component 4 works given that the system is functioning is given by P(A/S) ;
P(A/S) = {Means P(component 4 working and system also working)
divided by P(system is functioning)}
P(A/S) = {In numerator it is P(component 4 working) and in
denominator it is P(system working) = 1 - P(system is not working)}
Since we know that P(system not working) means that none of the components is working in system and it is given with the probability of 0.6 and since there are total of 5 components so P(system working) = 1 - 
.
Hence, P(A/S) = 
= 0.434.
In general, the average rate of change of f (x) on the interval a, b is given by f(b) – f(a) / b – a. The average rate of alteration of a function, f (x) on an interval is well-defined to be the variance of the function values at the endpoints of the interim divided by the difference in the x values at the endpoints of the interval. this is also known as the difference quotient that tells how on average, the y values of a function are changing in connection to variations in the x values. A positive or negative rate of change is applicable which match up to an increase or decrease in the y value among the two data points. It is called zero rate of change when a quantity does not change over time.
Its A. x=4
procedure: 3*equation1 - 2*equation2 ⇒ x=4
