Answer: An independent variable is exactly what it sounds like. It is a variable that stands alone and isn't changed by the other variables you are trying to measure. For example, someone's age might be an independent variable.
5h -2+ 9h
= (5h+ 9h) -2
= 14h -2
The final answer is 14h -2~
The equation that represents the graph of the ellipse is x² / 4 + y² / 100 = 1. (Correct choice: D)
<h3>What is the equation of the ellipse represented in the graph?</h3>
Herein we have a representation of an ellipse in the image attached aside, ellipses are characterized by the following <em>standard</em> formula:
(x - h)² / a² + (y - k)² / b² = 1 (1)
Where:
- (h, k) - Coordinates of the center
- a, b - Lengths of the semiaxes
Please notice that ellipse will be vertical if b > a, otherwise it will be horizontal. The graph exhibits a <em>vertical</em> ellipse centered at the origin and therefore we conclude that (h, k) = (0, 0) and b > a (b = 10, a = 2). Finally, the equation that represents the graph of the ellipse is x² / 4 + y² / 100 = 1. (Correct choice: D)
To learn more on ellipses: brainly.com/question/14281133
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Answer:
18 sticks of pepperoni
Step-by-step explanation:
In order to solve this problem, we have to find out how many pepperoni sticks are needed for just 1 pizza. If it takes 14 sticks to make 28 pizzas, that means it takes only half a stick to make a single pizza.
Now that we have this information, we can multiply 1/2 by 36 to find out how many sticks of pepperoni are needed to make 36 pizzas.
Therefore, it takes 18 sticks of pepperoni to make 36 pizzas. I hope this helps! Have a lovely day!! :)
I would solve the first equation for x and then sub that value into x in the second equation. That's the easiest way. x - 2y = 3 solved for x is x = 2y+3. Now sub that in for x in the second equation: 5(2y+3)+3y=2 and 10y + 15 + 3y = 2. 13y = -13, and y = -1. Now sub that y value into either equation to solve for x: x = 2(-1) + 3 gives us an x value of x = 1. Therefore, your solution to this system is (1, -1), first choice above.
