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Lena [83]
3 years ago
5

Find the following quantity. 103% of 19 =

Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0
19.57 because 100 percent is 19 and 1 percent is 0.19 so you times 0.19 by three and then add it on to 19
posledela3 years ago
3 0
19 × 1.03 = 19.57

The answer is 19.57.
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You walk 20 meters north, then 5 meters south. what is your displacement?
Viktor [21]
Sry this is completely off topic, but where do you go to ask questions? I can't seem to find it. The answer is C I think
4 0
3 years ago
Solve by the linear combination method (with or without multiplication) <br> 2x+3y= -17, 5x+2y = -4
Amiraneli [1.4K]
2x+3y= -17 
5x+2y= -4
You must cancel either the x or y out to solve so i'm going to cancel the x. 
-5(2x+3y= -17)
2(5x+2y= -4)
This simplifies to: 
-15x -15y=85
15x+4y= -8
The -15x and 15x cancel out leaving you: 
-15y=85 
4y= -8
You add them top numbers by the bottom and get: 
-11y=77
Then divide by -11 to get y by its self.
y= -7
Now that you know what y is just plug it in to either original problem. I will use the second one. 
5x + 2(-7) = -4
5x -14 = -4
5x = 10 
x = 2
So the answer is (2,-7) or x=2 and y=-7
6 0
3 years ago
Read 2 more answers
Assume a test for a disease has a probability 0.05 of incorrectly identifying an individual as infected (False Positive), and a
Nana76 [90]

Answer:

0.00002 = 0.002% probability of actually having the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test

Event B: Having the disease

Probability of having a positive test:

0.05 of 1 - 0.000001(false positive)

0.99 of 0.000001 positive. So

P(A) = 0.05*(1 - 0.000001) + 0.99*0.000001 = 0.05000094

Probability of a positive test and having the disease:

0.99 of 0.000001. So

P(A \cap B) = 0.99*0.000001 = 9.9 \times 10^{-7}

What is the probability of actually having the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{9.9 \times 10^{-7}}{0.05000094} = 0.00002

0.00002 = 0.002% probability of actually having the disease

6 0
3 years ago
0.6 divided by what equals 0.6?
xxTIMURxx [149]

Answer:

Step-by-step explanation:

1

7 0
3 years ago
Read 2 more answers
Find the length of the side of a square whose area is equal to the area of a rectangle with side measures 4.9 m and 1.6 m​
trapecia [35]

Given :

  • Area of square equals to the area of rectangle of sides 4.9m and 1.6m .

To find :-

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Solution :-

<u>As </u><u>we</u><u> know</u><u> </u><u>,</u>

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  • 4.9 * 1.6 = a²
  • a = √ 49/10 * 16/10
  • a = 7/10 * 4/10
  • a = 28/100
  • a = 0.28 m
6 0
3 years ago
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