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Bess [88]
3 years ago
14

Not sure which one, please help or give me clues to solve it.

Mathematics
2 answers:
diamong [38]3 years ago
8 0
Its the last one i think
ella [17]3 years ago
6 0
It's the second one.
Hope this helps
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8. A music store sells used CDs for $9. They buy used CDs for $4. You have $50 to
Marat540 [252]

Answer: 9x+4=50

Step-by-step explanation:

In this case, we're looking at how many you can buy, not how many CD's you own.

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3 years ago
If a bike is $125 how much will it be when its discounted by 20%
weeeeeb [17]

Answer:

160 pages.

Step-by-step explanation:

That is 125 - 0.20 * 125

= 125 - 25

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6 0
3 years ago
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The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as
bija089 [108]

Answer:

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(score of the 36 golfers was between 70 and 71)

\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}

P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%

P(70 \leq x \leq 71) = 47.7\%

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

8 0
3 years ago
Solve the equation −2w+4=−12. URGENT Solution
VMariaS [17]

Answer:

The solution is w=8

Step-by-step explanation:

we have

-2w+4=-12

Solve for w

That means -----> isolate the variable w

Subtract 4 both sides

-2w+4-4=-12-4

-2w=-16

Divide by -2 both sides

-2w/-2=-16/-2

w=8

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3 years ago
Write the number 6,007,200 in two different forms
erik [133]
1 way
six million, seven thousand, and two hundred.
6 0
3 years ago
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