Michael plots and connects the following points: A(-3,2), B(1,1), C(-3,4) and D(-5,-1). Which best describes the quadrilateral f
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So hmm notice the picture below
thus![\bf \cfrac{y}{tan(64^o)}=\cfrac{y}{tan(46^o)}-100\implies \cfrac{y}{tan(64^o)}-\cfrac{y}{tan(46^o)}=-100 \\\\\\ y\left[ \cfrac{1}{tan(64^o)}-\cfrac{1}{tan(46^o)} \right]=-100\implies y=\cfrac{-100}{\frac{1}{tan(64^o)}-\frac{1}{tan(46^o)}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7By%7D%7Btan%2864%5Eo%29%7D%3D%5Ccfrac%7By%7D%7Btan%2846%5Eo%29%7D-100%5Cimplies%20%0A%5Ccfrac%7By%7D%7Btan%2864%5Eo%29%7D-%5Ccfrac%7By%7D%7Btan%2846%5Eo%29%7D%3D-100%0A%5C%5C%5C%5C%5C%5C%0Ay%5Cleft%5B%20%5Ccfrac%7B1%7D%7Btan%2864%5Eo%29%7D-%5Ccfrac%7B1%7D%7Btan%2846%5Eo%29%7D%20%5Cright%5D%3D-100%5Cimplies%20y%3D%5Ccfrac%7B-100%7D%7B%5Cfrac%7B1%7D%7Btan%2864%5Eo%29%7D-%5Cfrac%7B1%7D%7Btan%2846%5Eo%29%7D%7D)
make sure your calculator is in Degree mode, since the angles are in degrees
thus
make sure your calculator is in Degree mode, since the angles are in degrees