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lukranit [14]
3 years ago
14

A bag contains 4 purple beads and 3 green beads. A bead is drawn and then replaced before drawing the second bead. Find the prob

ability both beads drawn are green.
A) 16/49
B) 6/7
C) 6/49
D) 9/49
Mathematics
2 answers:
Alex17521 [72]3 years ago
6 0

Answer:

9/49

Step-by-step explanation:

4 purple beads and 3 green beads= 7 beads

P( green) = green = total = 3/7

Replace the bead

4 purple beads and 3 green beads= 7 beads

P( green) = green = total = 3/7

P( green , replace, green) = 3/7 * 3/7 = 9/49

aivan3 [116]3 years ago
3 0
D) 9/49

if you pulled once, the probability would be 3/7. multiply 3/7*3/7 to get 9/49

hope this helps!
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8. Solve using any method.<br> 3y – 3 = 3x<br> -3x + 3y = -57
Ksivusya [100]

Answer:

No Solutions.

Step-by-step explanation:

I will solve your system by substitution.

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Step: Solve 3y−3=3x for y:

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3y=3x+3

(3y/3=3x+3)/3

(Divide both sides by 3)

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Step: Substitute x+1 for y in −3x+3y=−57:

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Answer:

The vehicle can travel 12 miles per gallon of gas.

Step-by-step explanation:

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