A bag contains 4 purple beads and 3 green beads. A bead is drawn and then replaced before drawing the second bead. Find the prob
ability both beads drawn are green.
A) 16/49
B) 6/7
C) 6/49
D) 9/49
2 answers:
Answer:
9/49
Step-by-step explanation:
4 purple beads and 3 green beads= 7 beads
P( green) = green = total = 3/7
Replace the bead
4 purple beads and 3 green beads= 7 beads
P( green) = green = total = 3/7
P( green , replace, green) = 3/7 * 3/7 = 9/49
D) 9/49
if you pulled once, the probability would be 3/7. multiply 3/7*3/7 to get 9/49
hope this helps!
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