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lukranit [14]
3 years ago
14

A bag contains 4 purple beads and 3 green beads. A bead is drawn and then replaced before drawing the second bead. Find the prob

ability both beads drawn are green.
A) 16/49
B) 6/7
C) 6/49
D) 9/49
Mathematics
2 answers:
Alex17521 [72]3 years ago
6 0

Answer:

9/49

Step-by-step explanation:

4 purple beads and 3 green beads= 7 beads

P( green) = green = total = 3/7

Replace the bead

4 purple beads and 3 green beads= 7 beads

P( green) = green = total = 3/7

P( green , replace, green) = 3/7 * 3/7 = 9/49

aivan3 [116]3 years ago
3 0
D) 9/49

if you pulled once, the probability would be 3/7. multiply 3/7*3/7 to get 9/49

hope this helps!
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Zoe had 3 1 /8 feet of orange ribbon. She used some ribbon to make a bow for a gift now she has 1 3 /8 feet of orange ribbon lef
Nastasia [14]

Answer:

Orange ribbon Zoe use is  1\frac{3}{4} \ feet.

Step-by-step explanation:

Given:

Zoe had 3 1 /8 feet of orange ribbon. She used some ribbon to make a bow for a gift now she has 1 3 /8 feet of orange ribbon left.

Now, to find the orange ribbon Zoe use.

Let the orange ribbon Zoe use be x.

Total orange ribbon Zoe had = 3\frac{1}{8} = \frac{25}{8} \ feet.

Ribbon Zoe had left = 1\frac{3}{8} =\frac{11}{8} \ feet.

Now, to get the orange ribbon Zoe use:

\frac{25}{8} -x=\frac{11}{8}

<em>Subtracting both sides by </em>\frac{11}{8}<em> we get:</em>

\frac{25}{8} -x-\frac{11}{8} =0

<em>Adding both sides by </em>x<em> we get:</em>

\frac{25}{8} -\frac{11}{8} =x

\frac{25-11}{8} =x

\frac{14}{8}=x

x=\frac{14}{8}

x=\frac{7}{4}

x=1\frac{3}{4}\ feet.

Therefore, orange ribbon Zoe use is 1\frac{3}{4} \ feet.

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Answer:

(-5.5, 3)

Step-by-step explanation:

\left(\frac{-4-7}{2}, \frac{-2+8}{2} \right)=(-5.5, 3)

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