A bag contains 4 purple beads and 3 green beads. A bead is drawn and then replaced before drawing the second bead. Find the prob

Question

2 years ago

14

ability both beads drawn are green.
A) 16/49
B) 6/7
C) 6/49
D) 9/49

2 answers:

Alex17521 [72] · Answer 1 · 2022-11-07T12:50:26+03:00

6 0

Answer:

9/49

Step-by-step explanation:

4 purple beads and 3 green beads= 7 beads

P( green) = green = total = 3/7

Replace the bead

4 purple beads and 3 green beads= 7 beads

P( green) = green = total = 3/7

P( green , replace, green) = 3/7 * 3/7 = 9/49

aivan3 [116] · Answer 2 · 2022-11-07T14:12:02+03:00

3 0

D) 9/49

if you pulled once, the probability would be 3/7. multiply 3/7*3/7 to get 9/49

hope this helps!