Which choice correctly shows the solution(s) of the equation x2 = 400?

Blake has a glass tank. First, he wants to put some marbles in it, all of the same volume. Then, he wants to fill the tank with

NeTakaya

Answer:

32 liters is the volume of the glass tank

3 0

2 years ago

Kara incorrectly factored 32x2 + 48x + 18 as shown. Describe her error and correctly factor the expression. 32x2 + 48x + 18 = 2(

aev [14]

Answer:

Kara incorrectly factored 2(16x^2 + 24x + 9) she did not find the correct factors when she factored out. The correct factored expression would be 2(4x+3)^2

Step-by-step explanation:

32x^2 + 48x + 18

2(16x^2 + 24x + 9)

2(16x^2 + 12x) (12x + 9)

2 4x(4x + 3) 3(4x + 3)

2(4x + 3)(4x + 3)

2(4x + 3)^2

3 0

3 years ago

The previous balance in your check register $234.67 . You make a deposit of 150.00 .You write a check for $63.23 . What is your

skelet666 [1.2K]

Answer:

321.44

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Can somebody help me? Thanks!

ICE Princess25 [194]

Answer: both our A

Step-by-step explanation:

8 0

3 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

2 years ago