Distance formula
D = √((x1 - x2)2 + (y1 - y2)2) We have three distances that we are dealing with. Between the Theater and the Park, between the Theater and the Pier, and between the Park and the pier. In both routes we have to go between the Theater and the Park. The distance between those is the same regardless of which way we go, so we can ignore doing the math for that. That leaves us two distances. Let's plug them in. Theater to PierD = √((0 - 10)2 + (3 - 9)2) = √(100 + 36) ≈ 11.6619 Park to PierD = √((2 - 10)2 + (1 - 9)2) = √(64 + 64) ≈ 11.3137 11.3 < 11.7
<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
Answer:(9y-7)(9y+7)
Step-by-step explanation:
81y^2-49
=(9y)^2-(7)^2
=(9y-7)(9y+7)
Answer:
The value of the maximum distance the spring will be compressed
x = 0.143 m= 14.3 cm
Step-by-step explanation:
Given data
Mass m = 1.5 kg
h = 0.9 m
k = 1500
Since the book is released from a height h = 0.9 m above the top of the spring. so the total distance
y = h + x
Now in that case for the spring


By rearranging the above equation we get

Put all the values in above equation we get

By solving the above equation we get
x = 0.143 m= 14.3 cm
This is the value of the maximum distance the spring will be compressed.