What is the vertex of the graph of f(x) = |x-3| + 11?
2 answers:
Answer:
(3,11)
Step-by-step explanation:
we find the vertex of
which is going to be (x,0)
and we add 11 (movement upward) so the vertex is (x,11)
vertex of g(x)
it is going to be when g(x)=0
and that only happens when x=3
so vertex (3,0)
so vertex of f(x)
(3,11)
if you don't believe i leave you the graph
The function f(x) = |x-3| +11 is in the vertex form which means vertex is (3,11)
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