What is the vertex of the graph of f(x) = |x-3| + 11?

Mathematics

2 answers:

Serga [27]2 years ago

6 0

Answer:

(3,11)

Step-by-step explanation:

we find the vertex of

$g(x)=|x-3|$ which is going to be (x,0)

and we add 11 (movement upward) so the vertex is (x,11)

vertex of g(x)

it is going to be when g(x)=0

and that only happens when x=3

so vertex (3,0)

so vertex of f(x)

(3,11)

if you don't believe i leave you the graph

weqwewe [10]2 years ago

4 0

The function f(x) = |x-3| +11 is in the vertex form which means vertex is (3,11)

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