Find the volume. Round to the nearest tenth.
1 answer:
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Answer:
A'(0, 1), B'(3, 1), C'(3, -1), D'(0, -1)
Step-by-step explanation:
Add (-1, 3) to each of the given points:
A' = A + (-1, 3) = (1-1, -2+3) = (0, 1) . . . . for example
The measure of ∠ACB will be 110°
<u><em>Explanation</em></u>
According to the diagram below, and
are the perpendicular bisectors of
and
respectively and they intersect side
at points
and
respectively.
So, and
Now, <u>according to the postulate</u>, ΔAPE and ΔCPE are congruent each other. Also, ΔCFQ and ΔBFQ are congruent to each other.
That means, ∠PCE = ∠PAE and ∠FCQ = ∠FBQ
As ∠CPQ = 78° , so ∠PCE + ∠PAE = 78° or, ∠PCE = ° and as ∠CQP = 62° , so ∠FCQ + ∠FBQ = 62° or, ∠FCQ =
°
Now, in triangle CPQ, ∠PCQ = 180°-(78° + 62°) = 180° - 140° = 40°
Thus, ∠ACB = ∠PCE + ∠PCQ + ∠FCQ = 39° + 40° + 31° = 110°
