Answer:
C: -2<x≤7
Step-by-step explanation:
- -2<x, as there is an open circle on -2
- x≤7 as there is a closed circle on 7
- Put them together, -2<x≤7
4(3+14c−12d)
=(4)(3+14c+−12d)
=(4)(3)+(4)(14c)+(4)(−12d)
=12+c−2d
=c−2d+12
The modulus of complex number can be computed with this equation:
|z|=sqrt(Re(z)^2+Im(z)^2)
z = -2-6i
Re(z)=-2, so Re(z)^2=4
Im(z)=-6, so Im(z)^2=36
|z|=sqrt(36+4)=sqrt(40)=6.3
Answer:
10
Step-by-step explanation:
