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Vlada [557]
3 years ago
6

A disease is spreading through a flock of 100 sheep. Let S(t) be the number of sick sheep t days after the outbreak. The disease

is spreading at a rate proportional to the product of the time elapsed and the number of sheep who do not have the disease. Suppose that 10 sheep had the disease initially. The mathematical model is:________
Mathematics
2 answers:
aksik [14]3 years ago
8 0

Answer:

módem an decandes frenses

Rainbow [258]3 years ago
7 0

Answer:

10 out of 100

Step-by-step explanation:

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Which of the following could be the graph of this equation?
Anna35 [415]

Answer: OPTION C.

Step-by-step explanation:

Given a function f(x), the range of the inverse of f(x) will be the domain of the function f(x) and the range of the domain of f(x) will be the range of the inverse function.

For example, if the point (2,1) belongs to f(x), then the point (1,2) belongs to the inverse of f(x).

Observe that in the graph of the function f(x) the point (-3,1) belongs to the function, then the point (1,-3) must belong to the inverse function.

Therefore, you need to search the option that shown the graph wich contains the point (1,-3).

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This is the graph of the option C.

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4 years ago
1400 dollars is placed in an account with an annual interest rate of 7.25%. To the nearest tenth of a year, how long will it tak
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6 0
3 years ago
In an international film festival, a penal of 11 judges is formed to judge the best film. At last two films FA and FB were consi
valentina_108 [34]

Answer:

The answer is "0.4329 ".

Step-by-step explanation:

P( three in favor of FA)

Select 3 out of 6 FA supporters then select 2 out of 5 FB supportive judges  

=\frac{^{6}_{C_{3}}\times ^{5}_{C_{2}}}{^{11}_{C_{5}}}\\\\=\frac{\frac{6!}{3!(6-3)!}\times \frac{5!}{2!(5-2)!}}{\frac{11!}{5!(11-5)!}}\\\\=\frac{\frac{6!}{3! \times 3!}\times \frac{5!}{2! \times 3!}}{\frac{11!}{5! \times 6!}}\\\\=\frac{\frac{6 \times 5 \times 4 \times 3!}{3 \times 2  \times 1\times 3!}\times \frac{5  \times 4  \times 3!}{2 \times 1 \times 3!}}{\frac{11  \times10  \times 9  \times 8 \times 7  \times 6! }{5 \times 4 \times 3  \times 2  \times 1 \times 6!}}\\\\

=\frac{ (5 \times 4) \times(5  \times 2)}{(11  \times 3  \times 2 \times 7 )}\\\\=\frac{ 20 \times 10 }{(11 \times 42)}\\\\=\frac{ 200 }{462}\\\\=\frac{100 }{231}\\\\=0.4329

6 0
3 years ago
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