Answer:
https://www.ringgold.org/cms/lib/PA01916235/Centricity/Domain/227/Algebra%20I%20Keystone%20Review%20Packet%20Answer%20Key.pdf
there you go just a copy and a paste
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
Answer: Are you ok?
Step-by-step explanation:
So I went from graph to slope intercept, So you take your x(Fat(g)) and your y(Calories) to solve.
The slope-intercept form for a line with the coordinates of (25,590) and (44,830) is:
y= 12.63x + 274.21
(results are in decimal form, rounded to the nearest 100th)
For Example: y=12.63(125)+274.21
y=1,852.96
