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Inessa05 [86]
3 years ago
5

An angle is 21 degree more than twice its complement find it

Mathematics
1 answer:
jekas [21]3 years ago
5 0

Answer: 67°

Step-by-step explanation:

Complementary angle refers to the angle that when added together will be equal to 90°.

Let the measurement of the angle's complement be x.

Therefore, the angles are x and 2x + 21. Since it's a complementary angle, therefore,

x + 2x + 21 = 90

3x + 21 = 90

3x = 90 - 21

3x = 69

x = 69°/3

x = 23°

Therefore, the angle will be:

= 2x + 21

= 2(23°) + 21°

= 46° + 21°

= 67°

The angle is 67°.

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Simplify 2(x - 3) + 7(x + 2)
lyudmila [28]

Answer:

9x + 8.

Step-by-step explanation:

2(x - 3) + 7(x + 2)

= 2x - 6 + 7x + 14

= 2x + 7x - 6 + 14

= 9x + 8.

Hope this helps!

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What is 1+1???? I HAVE NO IDEA PLEASE HELP!!!
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Answer:

Step-by-step explanation:

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Prove algebraically that each expression has the same value by evaluating each expression for y=5:
Illusion [34]

Answer:

See explanation

Step-by-step explanation:

Given two expressions

7(3y-5)-2(10+4y)

and

13y-55

Substitute y = 5 into each expression:

1.

7(3y-5)-2(10+4y)\\ \\=7(3\cdot 5-5)-2(10+4\cdot 5)\\ \\=7\cdot (15-5)-2\cdot (10+20)\\ \\=7\cdot 10-2\cdot 30\\ \\=70-60\\ \\=10

2.

13y-55\\ \\=13\cdot 5-55\\ \\=65-55\\ \\=10

As you can see the results are the same.

7 0
3 years ago
Tessa bought stock in a restaurant for $188.00. Her stock is now worth $240.64. What is the percentage increase of the value of
Vesnalui [34]

Answer:

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Step-by-step explanation:

22 %

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3 years ago
Read 2 more answers
1. Answer the following questions. (a) Check whether or not each of f1(x), f2(x) is a legitimate probability density function f1
kobusy [5.1K]

Answer:

f1 ( x ) valid pdf . f2 ( x ) is invalid pdf

k = 1 / 18 , i ) 0.6133 , ii ) 0.84792

Step-by-step explanation:

Solution:-

A) The two pdfs ( f1 ( x ) and f2 ( x ) ) are given as follows:

                      f_1(x) = \left \{ {{0.5(3x-x^3) } .. 0 < x < 2  \atop {0} } \right. \\\\f_2(x) = \left \{ {{0.3(3x-x^2) } .. 0 < x < 2  \atop {0} } \right. \\

- To check the legitimacy of a continuous probability density function the area under the curve over the domain must be equal to 1. In other words the following:

                    \int\limits^a_b {f_1( x )} \, dx = 1\\\\ \int\limits^a_b {f_2( x )} \, dx = 1\\

- We will perform integration of each given pdf as follows:

                    \int\limits^a_b {f_1(x)} \, dx  = \int\limits^2_0 {0.5(3x - x^3 )} \, dx \\\\\int\limits^a_b {f_1(x)} \, dx  = [ 0.75x^2 - 0.125x^4 ]\limits^2_0\\\\\int\limits^a_b {f_1(x)} \, dx  = [ 0.75*(4) - 0.125*(16) ]\\\\\int\limits^a_b {f_1(x)} \, dx  = [ 3 - 2 ] = 1\\

                    \int\limits^a_b {f_2(x)} \, dx  = \int\limits^2_0 {0.5(3x - x^2 )} \, dx \\\\\int\limits^a_b {f_1(x)} \, dx  = [ 0.75x^2 - \frac{x^3}{6}  ]\limits^2_0\\\\\int\limits^a_b {f_1(x)} \, dx  = [ 0.75*(4) - \frac{(8)}{6} ]\\\\\int\limits^a_b {f_1(x)} \, dx  = [ 3 - 1.3333 ] = 1.67 \neq 1 \\

Answer: f1 ( x ) is a valid pdf; however, f2 ( x ) is not a valid pdf.

B)

- A random variable ( X ) denotes the resistance of a randomly chosen resistor, and the pdf is given as follows:

                     f ( x ) = kx   if  8 ≤ x ≤ 10

                                0  otherwise.

- To determine the value of ( k ) we will impose the condition of validity of a probability function as follows:

                       \int\limits^a_b {f(x)} \, dx = 1\\

- Evaluate the integral as follows:

                      \int\limits^1_8 {kx} \, dx = 1\\\\\frac{kx^2}{2} ]\limits^1^0_8 = 1\\\\k* [ 10^2 - 8^2 ] = 2\\\\k = \frac{2}{36} = \frac{1}{18}... Answer

- To determine the CDF of the given probability distribution we will integrate the pdf from the initial point ( 8 ) to a respective value ( x ) as follows:

                      cdf = F ( x ) = \int\limits^x_8 {f(x)} \, dx\\\\F ( x ) = \int\limits^x_8 {\frac{x}{18} } \, dx\\\\ F ( x ) = [ \frac{x^2}{36} ] \limits^x_8\\\\F ( x ) = \frac{x^2 - 64}{36}

To determine the probability p ( 8.6 ≤ x ≤ 9.8 ) we will utilize the cdf as follows:

                    p ( 8.6 ≤ x ≤ 9.8 ) = F ( 9.8 ) - F ( 8.6 )

                    p ( 8.6 ≤ x ≤ 9.8 ) = \frac{(9.8)^2 - 64}{36} - \frac{(8.6)^2 - 64}{36} = 0.61333

ii) To determine the conditional probability we will utilize the basic formula as follows:

                p ( x ≤ 9.8  | x ≥ 8.6 ) = p ( 8.6 ≤ x ≤ 9.8 ) / p ( x ≥ 8.6 )

                p ( x ≤ 9.8  | x ≥ 8.6 ) = 0.61333 / [ 1 - p ( x ≤ 8.6 ) ]

                p ( x ≤ 9.8  | x ≥ 8.6 ) = 0.61333 / [ 1 - 0.27666 ]

                p ( x ≤ 9.8  | x ≥ 8.6 ) = 0.61333 / [ 0.72333 ]

                p ( x ≤ 9.8  | x ≥ 8.6 ) = 0.84792 ... answer

3 0
3 years ago
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