The function of the object height is an illustration of a projectile motion
The object will never hit the ground
<h3>How to determine when the object hits the ground?</h3>
The function is given as:
h=16t^2+80t+96.
When the object hits the ground, h = 0
So, we have:
16t^2+80t+96 = 0
Divide through by 16
t^2+5t+6 = 0
Expand
t^2 + 3t + 2t + 6 = 0
Factorize
t(t + 3) + 2(t + 3) = 0
Factor out t + 3
(t + 2)(t + 3) = 0
Solve for t
t = -2 or t = -3
The time (t) cannot be negative.
Hence, the object will never hit the ground
Read more about projectile motion at:
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Answer:b
Step-by-step explanation:
Answer:
32/20=1.6
Step-by-step explanation:
9514 1404 393
Answer:
y = 1/4x + 5
Step-by-step explanation:
The given line has a "rise" of -8 for a "run" of 2, so a slope of ...
m = rise/run = -8/2 = -4
The perpendicular line will have a slope that is the opposite of the reciprocal of this slope. Its slope will be ...
-1/m = -1/(-4) = 1/4
The equation you're looking for will have an x-coefficient of 1/4. The suitable choice is ...
y = 1/4x + 5 . . . . the third choice