Answer:The circumference = π x the diameter of the circle (Pi multiplied by the diameter of the circle). Simply divide the circumference by π and you will have the length of the diameter. The diameter is just the radius times two, so divide the diameter by two and you will have the radius of the circle!Hope it helps!!!!
Step-by-step explanation:
Answer:
False.
Step-by-step explanation:
This is NOT an example of a binomial random variable, because a binomial random variable can only have TWO possible outcomes: success or failure. In the case of rolling a die, there are SIX possible outcomes: 1, 2, 3, 4, 5, or 6.
So, rolling a 6-sided die and counting the number of each outcome that occurs is NOT a binomial random variable.
Hope this helps!
If she used all of her yarn, she'd have 24 pieces. If she wanted 1.25 left, she'd have ten less because 24 • .125 = 8, and 1/4 of eight = 2, and 2 + 8 = 10.
So she'd have 14 pieces.
I’m here to help.
For this question here you need to use the sine formula for the area of a triangle and figure out the area of the sector
I’ll take you through it step-by-step
Area of the arc:
We only have 68.9 degrees out of 360 and we need to use the formula for the area of a circle.
Formula of a circle = pi x radius squared
68.9/360 x pi x 86.1184= 51.78 (2dp)
Area of triangle:
As you can see we have no height so we must use the sine formula for the area of a triangle.
Formula= 1/2abSinC
You should end up with
0.5 x 9.28x 9.28 x Sin(68.9)= 40.17 (2dp)
Now since you want the area of the segment shaded, just find the difference between these two values.
51.78-40.17 = 11.61
Answer= 11.6cm squared
Hope this helped!
The formula for the future value A, given annual interest rate r, number of years t, and deposit amount P can be written as
... A = P(1 +r/12)((1+r/12)^(12t) -1)/(r/12)
Filling in the given numbers, you have
... A = 200(1+.0275/12)((1+.0275/12)^(12·39) -1)/(.0275/12) ≈ 167,868.30
The appropriate choice is $167,868.30.
_____
The formula is the one for the sum of a geometric series. It can be useful to consider the last deposit made as the first term of the series.
