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Lisa [10]
3 years ago
11

I'm not sure what to do on these

Mathematics
1 answer:
stepan [7]3 years ago
8 0
The first is either b or c and the second is d. Sorry for not telling yoi what the answer is for the first one
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Why does dividing by 100 shift each digit two places to the right?
alekssr [168]
The answer is D. If you divide 1000 by 100, it is 10. 10 is equal to 1/100 of its previous value of 1000.
3 0
3 years ago
A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0
3 years ago
What is 328/25 as a whole number
bagirrra123 [75]

Answer:

13.12

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr
dybincka [34]

Answer:

  \log{\dfrac{3\sqrt{x}(x^3+4)}{2}}

Step-by-step explanation:

\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}

__

The applicable rules of logarithms are ...

  log(ab) = log(a) +log(b)

  log(a/b) = log(a) -log(b)

  log(a^b) = b·log(a)

3 0
3 years ago
If andre collects $9.80, how many cups did he sell?
barxatty [35]

Answer:

we need more information

5 0
2 years ago
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