Using the Pythagorean Theorem, we have that the distance from home plate to second base is about 127 feet.
<h3>What is the Pythagorean Theorem?</h3>
The Pythagorean Theorem relates the length of the legs 
and 
of a right triangle with the length of the hypotenuse h, stating that the hypotenuse squared is the <u>sum of the legs squared</u> of the triangle, according to the following equation:
The distance between each consecutive base is of 90 feet, hence the distance from home plate to 2nd base is the hypotenuse of a <u>right triangle in which the legs are of 90 feet</u>, being the distances from home plate to 1st base and 1st base to 2nd base.
Then:
h² = 90² + 90²
h = sqrt(90² + 90²)
h = 127 feet.
The distance from home plate to second base is about 127 feet.
More can be learned about the Pythagorean Theorem at brainly.com/question/654982
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Answer:
π2,√80,12
Step-by-step explanation:
π2= 6.28
√80= about 8
12=12
Hope I could help!
He did not perform enough trials. The more trials you perform, the closer it gets to the predicted outcome.
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
